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fenix001 [56]
3 years ago
15

Write code that inserts useritems into the output string stream itemsoss until the user enters "exit". each item should be follo

wed by a space
Computers and Technology
1 answer:
Yuliya22 [10]3 years ago
5 0
If user output is ''red purble yellow exit'': red purple yellow  import java.util.Scanner;  import java. io.PrintWriter;  import java. io.StringWriter;    public class StringStreamOutput {   public static void main (String [] args) {   Scanner snr = new Scanner(Scanner.in);   Stringuseritem = '''';    StringWriter itemcharStream = new StringWriter();  PrinterWriter itemsOSS = new PrintWriter(itemcharStream);    System.out.printIn(''Enter items (type Exit to open):'');  useritem = scnr.next();    while (!userItems.Equals(''Exit'')) {  /*Your solution goes here*/     UserItem = scnr.nxt();    }     useritem = itemCharStream.toString()   System.out.printin(useritem);     return;     }    }
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Databases offer many security features including passwords to provide authentication, access levels to determine who can access
Murljashka [212]

Answer:

True

Explanation:

When using databases in a project, not everyone has the same access level, e.g the database admin may have the highest level of access (access to data on live mode), the software testers have their own level of access (access to data on test mode) and so on.  

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4 years ago
Which of the following is not an assessment of your fitness to drive
Ivan

Answer:

C. Am I carrying money?

Explanation:

The options are:

A. Am I awake and alert?

B. Am I emotionally sound?

C. Am I carrying money?

D. Am I physically able?

The correct option is certainly C. Am I carrying money? It can also be a concern if you are worrying since we don't have money. However, here its mentioned, we are not carrying, and it's not like we don't have money, and hence, it is not going to affect our mindset. Hence, it is not an assessment of anybody's fitness to drive.

3 0
4 years ago
Assignment Background Video games have become an outlet for artists to express their creative ideas and imaginations and a great
Sphinxa [80]

Answer:

Code

import csv

def open_file():

try:

fname=input("Enter the filename to open (xxx.yyy): ")

fp=open(fname,encoding='utf-8')

return fp

except FileNotFoundError:

print("File not found! Please Enter correct filename with extension")

return open_file()

def read_file(fp):

fields = []

rows = []

csvreader = list(csv.reader(fp))

# skiped 1 row because it contains field name

fields = csvreader[0]

D1={}

D2={}

D3={}

# accessing the data of csv file

for line in csvreader[1:]:

name = line[0].lower().strip()

platform = line[1].lower().strip()

if line[2]!='N/A':

year = int(line[2])

else:

year=line[2]

genre = line[3].lower().strip()

publisher = line[4].lower().strip()

na_sales = float(line[5])

eur_sales = float(line[6])

jpn_sales = float(line[7])

other_sales = float(line[8])

global_sales=(na_sales+eur_sales+jpn_sales+other_sales)*1000000

if name not in D1:

D1[name]=[]

D1[name].append((name, platform, year, genre, publisher,global_sales))

if genre not in D2:

D2[genre]=[]

D2[genre].append((genre, year, na_sales, eur_sales,jpn_sales, other_sales, global_sales))

if publisher not in D3:

D3[publisher]=[]

D3[publisher].append((publisher, name, year, na_sales,eur_sales, jpn_sales, other_sales, global_sales))

# sorting

temp={}

# sorting keys

for Keys in sorted (D1) :

ls=D1[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

temp[Keys]=ls

D1=temp.copy()

temp={}

# sorting keys

for Keys in sorted (D2) :

ls=D2[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

temp[Keys]=ls

D2=temp.copy()

temp={}

# sorting keys

for Keys in sorted (D3) :

ls=D3[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

temp[Keys]=ls

D3=temp.copy()

return D1,D2,D3

 

def main():

fp=open_file()

D1,D2,D3=read_file(fp)

# displaying the row_count in dictionaries

cnt=0

for d in D1:

cnt+=1

print(cnt)

print("\n\n=============================================\n\n")

cnt=0

for d in D2:

cnt+=1

print(cnt)

print("\n\n=============================================\n\n")

cnt=0

for d in D3:

cnt+=1

print(cnt)

print("\n\n=============================================\n\n")

 

 

if __name__=="__main__":

main()

Explanation:

see code and see output attached

7 0
3 years ago
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