20 in I’m for sure on this answer
Answer with explanation:
In Δ ABC and ΔD BC
∠A=∠D-------Given
∠ABC=∠DCB-------Each being 90° given in the Diagram.
Side, BC is Common.
⇒⇒Δ ABC ≅ ΔD BC-------[AAS]
When two triangles are congruent , their areas are equal.
So, Area(ABC)=Area (DCB)
Option B :⇒ A AS
Answer:
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Step-by-step explanation:
sorry my bad copy paste error
Answer:
7). up 4 over 4
8). up 1 over 2
Step-by-step explanation:
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Answer: The answer is (B) ∠SYD.
Step-by-step explanation: As mentioned in the question, two parallel lines PQ and RS are drawn in the attached figure. The transversal CD cut the lines PQ and RS at the points X and Y respectively.
We are given four angles, out of which one should be chosen which is congruent to ∠CXP.
The angles lying on opposite sides of the transversal and outside the two parallel lines are called alternate exterior angles.
For example, in the figure attached, ∠CXP, ∠SYD and ∠CXQ, ∠RYD are pairs of alternate exterior angles.
Now, the theorem of alternate exterior angles states that if the two lines are parallel having a transversal, then alternate exterior angles are congruent to each other.
Thus, we have
∠CXP ≅ ∠SYD.
So, option (B) is correct.