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Butoxors [25]
3 years ago
12

PHYSICS PLEASE HELP

Physics
2 answers:
Likurg_2 [28]3 years ago
8 0

1.)Answer:

The correct answer is C.

Explanation:

Displacement is a vector quantity so it may be either positive or negative. As per convention, acceleration taken as positive when moves downward direction. But, in our case, acceleration towards downward taken as negative, so displacement should also be negative because negative sign only indicate its downward direction.

2.) Answer

The correct answer is C. The time won't change, but horizontal distance will double.

Explanation:

First case

velocity = v = 20 m/s

Height = h = 10 m

We need to calculate time (t) and horizontal distance (x)

using 2nd equation of motion

h = vt + 0.5 gt²

As initial vertical velocity is 0. So

h = 0.5(9.8)t²

It can be see that time does not depends on initial velocity, so it won't change

to calculate x

x = vt

It can be see that horizontal distance will double because depends on velocity.

3.)Question

Illustration:

Day 1: 10 km west and spent night at A.

Day 2: 10 km west and night in a tent B.

Day 3: 20 km west and then they turned around and went back to the home because Jerry left his allergy medicine.

Day 4: 30 km North to the point D.

Answer

The correct answer is C.

Explanation:

On Day 1, Day 2 and Day 3, they move towards west 40 km from home and then turned back to home because Jerry forget his medicine. Thus the total distance is 80 km but the displacement is zero because displacement is the measure from initial to final position. As initial and final position is same at the end of 3rd day so displacement is zero. Fourth day, They move towards north 30 km and hence total distance is 110 km. And total displacement is only 30 km.

4.) Answer:

The correct Answer is A.

Explanation:

To calculate horizontal distance (x), we only need to find the horizontal component of velocity that is

vₓ = v Cos (70°)

vₓ = 41 m/s

As we know that x = vₓ t

So,

x = 41t

5.) Answer

The correct Answer is B.

Explanation:

Displacement is a vector quantity so it depends on direction. As Sally moves 10m forward and then 5m backward, So his total displacement is 5m. While the distance is scalar quantity independent of direction. So the total distance covered by Sally is 15m which is 10m greater than the displacement.  

6.)Answer

The correct answer is A.

Explanation:

Consider

horizontal(h)= 6m

vertical = Xm

Hypotenuse(H) = ?

Angle = 37°

As we know that

H×Cos∅ = h

So,

H = h ÷ Cos(∅)

 = 6 ÷ Cos(37)

H = 7.5 m    

7.) Answer:

The correct answer is D.

Explanation:

In projectile motion, horizontal distance depends on initial velocity and angle with ground. So as the player increase the velocity of the ball, more distance will be covered. As far as he increase the angle upto 45° with the ground, the horizontal distance will increase. That's why the player should increase the ball's initial velocity and kick it at a 45° angle.

8.)Answer:

The correct Answer is B.

Explanation:

Consider

Vector A  = 3m

Vector B  = 4m

Angle = ?

As the angle ∅ is created between vectors C and A.

we know that

tan∅ = vertical ÷ horizontal

tan∅ = 4 ÷ 3

∅ = tan⁻¹ (1.33)

∅ = 53.1°

9.) Answer:

The correct Answer is C.

Explanation:

Projectile motion depends on initial velocity and initial angle with ground. As far as we increase the velocity of the ball, more distance will be covered. As it also depends on angle, So as far as we increase the angle up to 45° with the ground, the horizontal distance will increase. But when the angle is above 45°, increasing angle decrease the horizontal distance.

10.) Answer:

The correct Answer is B.

Explanation:

Given data :

∅ = 20°

initial velocity = 40 m/s

As we need to find the vertical component of velocity

So, initial upward velocity = initial velocity × Sin∅ = 40 × Sin 20°

            initial upward velocity = 13.68 m/s

11.)Answer:

The correct Answer is B.

Explanation:

The projectile motion depends on the angle with the horizontal.As far as we increase the angle up to 45° with the ground, the distance will increase. But when the angle is above 45°, increasing angle decrease the horizontal distance.

12.) Answer:

The correct answer is D.

Explanation:

Given data

Initial speed = V₀ =40 m/s

angle = 60°

g = 9.81 m/s²

First we need to find initial vertical velocity (V)

V = V₀ Sin∅

V = 34.64 m/s

3rd equation of motion

2gh = V₁² - V²

As we need to find maximum height so at highest point vertical final velocity (V₁) = 0

So,

h = V² ÷ 2g

= 34.64² ÷ 2×9.81

                             h = 61.2 m

13.) Answer:

The correct answer is C.

Explanation:

A bird flying in the air is 3D motion as the bird move up, down, right, left all the possible direction. A leaf falling from a tree is also a 3D motion because a leaf never fall in absolute vertical manner. A lady bug crawling on a soccer ball also 3D. If lady bug crawling on a plane like floor then it is 2D but now lady bug crawling on soccer ball which is in spherical shape so it is also 3D motion. Only train travelling along a track is 2D because train cannot move up and down and the track of train is in a plane. So it is 2D motion.  

vaieri [72.5K]3 years ago
6 0

1.)Answer:

The correct answer is C.

Explanation:

Displacement is a vector quantity so it may be either positive or negative. As per convention, acceleration taken as positive when moves downward direction. But, in our case, acceleration towards downward taken as negative, so displacement should also be negative because negative sign only indicate its downward direction.

2.) Answer

The correct answer is C. The time won't change, but horizontal distance will double.

Explanation:

First case

velocity = v = 20 m/s

Height = h = 10 m

We need to calculate time (t) and horizontal distance (x)

using 2nd equation of motion

h = vt + 0.5 gt²

As initial vertical velocity is 0. So

h = 0.5(9.8)t²

It can be see that time does not depends on initial velocity, so it won't change

to calculate x

x = vt

It can be see that horizontal distance will double because depends on velocity.

3.)Question

Illustration:

Day 1: 10 km west and spent night at A.

Day 2: 10 km west and night in a tent B.

Day 3: 20 km west and then they turned around and went back to the home because Jerry left his allergy medicine.

Day 4: 30 km North to the point D.

Answer

The correct answer is C.

Explanation:

On Day 1, Day 2 and Day 3, they move towards west 40 km from home and then turned back to home because Jerry forget his medicine. Thus the total distance is 80 km but the displacement is zero because displacement is the measure from initial to final position. As initial and final position is same at the end of 3rd day so displacement is zero. Fourth day, They move towards north 30 km and hence total distance is 110 km. And total displacement is only 30 km.

4.) Answer:

The correct Answer is A.

Explanation:

To calculate horizontal distance (x), we only need to find the horizontal component of velocity that is

vₓ = v Cos (70°)

vₓ = 41 m/s

As we know that x = vₓ t

So,

x = 41t

5.) Answer

The correct Answer is B.

Explanation:

Displacement is a vector quantity so it depends on direction. As Sally moves 10m forward and then 5m backward, So his total displacement is 5m. While the distance is scalar quantity independent of direction. So the total distance covered by Sally is 15m which is 10m greater than the displacement.  

6.)Answer

The correct answer is A.

Explanation:

Consider

horizontal(h)= 6m

vertical = Xm

Hypotenuse(H) = ?

Angle = 37°

As we know that

H×Cos∅ = h

So,

H = h ÷ Cos(∅)

  = 6 ÷ Cos(37)

H = 7.5 m    

7.) Answer:

The correct answer is D.

Explanation:

In projectile motion, horizontal distance depends on initial velocity and angle with ground. So as the player increase the velocity of the ball, more distance will be covered. As far as he increase the angle upto 45° with the ground, the horizontal distance will increase. That's why the player should increase the ball's initial velocity and kick it at a 45° angle.

8.)Answer:

The correct Answer is B.

Explanation:

Consider

Vector A  = 3m

Vector B  = 4m

Angle = ?

As the angle ∅ is created between vectors C and A.

we know that

tan∅ = vertical ÷ horizontal

tan∅ = 4 ÷ 3

∅ = tan⁻¹ (1.33)

∅ = 53.1°

9.) Answer:

The correct Answer is C.

Explanation:

Projectile motion depends on initial velocity and initial angle with ground. As far as we increase the velocity of the ball, more distance will be covered. As it also depends on angle, So as far as we increase the angle up to 45° with the ground, the horizontal distance will increase. But when the angle is above 45°, increasing angle decrease the horizontal distance.

10.) Answer:

The correct Answer is B.

Explanation:

Given data :

∅ = 20°

initial velocity = 40 m/s

As we need to find the vertical component of velocity

So, initial upward velocity = initial velocity × Sin∅ = 40 × Sin 20°

             initial upward velocity = 13.68 m/s

11.)Answer:

The correct Answer is B.

Explanation:

The projectile motion depends on the angle with the horizontal.As far as we increase the angle up to 45° with the ground, the distance will increase. But when the angle is above 45°, increasing angle decrease the horizontal distance.

12.) Answer:

The correct answer is D.

Explanation:

Given data

Initial speed = V₀ =40 m/s

angle = 60°

g = 9.81 m/s²

First we need to find initial vertical velocity (V)

V = V₀ Sin∅

V = 34.64 m/s

3rd equation of motion

2gh = V₁² - V²

As we need to find maximum height so at highest point vertical final velocity (V₁) = 0

So,

h = V² ÷ 2g

 = 34.64² ÷ 2×9.81

                              h = 61.2 m

13.) Answer:

The correct answer is C.

Explanation:

A bird flying in the air is 3D motion as the bird move up, down, right, left all the possible direction. A leaf falling from a tree is also a 3D motion because a leaf never fall in absolute vertical manner. A lady bug crawling on a soccer ball also 3D. If lady bug crawling on a plane like floor then it is 2D but now lady bug crawling on soccer ball which is in spherical shape so it is also 3D motion. Only train travelling along a track is 2D because train cannot move up and down and the track of train is in a plane. So it is 2D motion.  

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The expression for Bernoulli's Equation is as follows:

P_1+\frac{1}{2}pv_1^2+pgy_1=P_2+\frac{1}{2}pv^2_2+pgy_2

pgy_1=\frac{1}{2}pv^2_2 +pgy_2

v_2=\sqrt{2g(y_1-y_2)}

where;

P₁ and P₂ = initial and final pressure.

v₁ and v₂ = initial and final fluid velocity

y₁ and y₂ = initial and final height

p = density

g = acceleration due to gravity

So, from our given parameters; let's replace

v₁ = 0 m/s ; y₁ = 0.35 m ; y₂ = 0 m ; g = 9.8 m/s²

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v₂ = \sqrt{2*9.8*(0.35-0)}

v₂ = \sqrt {6.86}

v₂ = 2.61916

v₂ ≅ 2.62 m/s

Similarly, using the expression of the continuity for water flowing through the spigot into the cylinder; we have:

v₂A₂ = v₃A₃

v₂r₂² = v₃r₃²

where;

v₂r₂ = velocity of the fluid and radius at the spigot

v₃r₃ = velocity of the fluid and radius at the cylinder

v_3 = \frac{v_2r_2^2}{v_3^2}

where;

v₂ = 2.62 m/s

r₂ = 1.5 mm

r₃ = 1.0 cm

we have;

v₃ = (2.62  m/s)* (\frac{1.5mm^2}{1.0mm^2} )

v₃ = 0.0589 m/s

∴ velocity  of the fluid in the cylinder =  0.0589 m/s

So, in an open-closed system we are dealing with; the frequency can be calculated by using the expression;

f=\frac{v_s}{4(h-v_3t)}

where;

v_s = velocity of sound

h = height of the fluid

v₃ = velocity  of the fluid in the cylinder

f=\frac{343}{4(0.40-(0.0589)(0.4)}

f= \frac{343}{0.6576}

f = 521.59 Hz

∴ The frequency f = 521.59 Hz

b)

What are the rate at which the frequency is changing (Hz/s) when the cylinder has been filling for 4.0 s?

The rate at which the frequency is changing is related to the function of time (t) and as such:

\frac{df}{dt}= \frac{d}{dt}(\frac{v_s}{4}(h-v_3t)^{-1})

\frac{df}{dt}= -\frac{v_s}{4}(h-v_3t)^2(-v_3)

\frac{df}{dt}= \frac{v_sv_3}{4(h-v_3t)^2}

where;

v_s (velocity of sound) = 343 m/s

v₃ (velocity  of the fluid in the cylinder) = 0.0589 m/s

h (height of the cylinder) = 0.40 m

t (time) = 4.0 s

Substituting our values; we have ;

\frac{df}{dt}= \frac{343*0.0589}{4(0.4-(0.0589*4.0))^2}

= 186.873

≅ 186.9 Hz/s

∴ The rate at which the frequency is changing = 186.9 Hz/s  when the cylinder has been filling for 4.0 s.

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