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Rus_ich [418]
4 years ago
12

What force must the people overcome in order to lift the rock? (rock on one end and two guys on the other end)

Physics
1 answer:
KATRIN_1 [288]4 years ago
5 0
I think it is gravity 
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The landing of a spacecraft is cushioned with the help of airbags. During its landing on Mars, the velocity of downward fall is
maria [59]
You can use the impulse momentum theorem and just subtract the two momenta.
P1 - P2 = (16-1.2)(11.5e4)=1702000Ns
If you first worked out the force and integrated it over time the result is the same
5 0
3 years ago
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Suppose that while moving into an apartment you move a refrigerator into place by sliding it across the floor. The refrigerator w
sweet-ann [11.9K]

Answer:

358 N

Explanation:

F=\mu N where F is the force, \mu is the coefficient of static friction between the floor and the refrigerator and N is the weight

Normally, N=mg hence F=\mu mg where m is the mass of object and g is the acceleration due to gravity

In this case, N is given as 895 N and the coefficient of static friction between the floor and the refrigerator is 0.400 hence substituting them in the formula we obtain

F=\mu N= 0.4\times 895 N= 358 N

4 0
4 years ago
Is it true or false
tester [92]

Answer:

false

Explanation:

8 0
2 years ago
A spring is compressed so that it has 7.2 J of elastic potential energy. A 0.3 kg ball is placed on top of the spring. When the
VLD [36.1K]

The height of the ball is 2.45 m.

To calculate the height of the ball, we use the formula below.

<h3>Formula</h3>
  • E = mgh................ Equation 1

Where:

  • E = Elastic energy of the spring
  • m = mass of the ball
  • h = height of the ball
  • g = acceleration due to gravity.

make h the subject of the equation

  • h = E/mg...............Equation 2

From the question,

Given:

  • E = 7.2 J
  • m = 0.3 kg
  • g = 9.8 m/s²

Substitute these  values into equation 2

  • h = 7.2/(0.3×9.8)
  • h = 7.2/2.94
  • h = 2.45 m

Hence, The height of the ball is 2.45 m.

Learn more about height here: brainly.com/question/1739912


5 0
3 years ago
Review question please take a look and help
Keith_Richards [23]
4!!!!!!!!!!!!!!!!!!!!!!!
4 0
3 years ago
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