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3 years ago

A car is moving in a straight line with the same speed of 100 m/s ,the acceleration in this

Physics

1 answer:

Amiraneli [1.4K]3 years ago

4 0

Answer:

a = 0m/s²

Explanation:

Average acceleration = (change in velocity)/(time it takes). Since the car's change in velocity is zero, its acceleration is zero.

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A gas exerts less pressure when it has a

Vika [28.1K]

The molecules are continually colliding with each other and with the walls of the container. When a molecule collides with the wall, they exert small force on the wall The pressure exerted by the gas is due to the sum of all these collision forces.The more particles that hit the walls, the higher the pressure.

4 0

3 years ago

Time: distance: direction:velocity

juin [17]

Do you want the formula?

7 0

3 years ago

How much work is required to accelerate a proton from rest up to a speed of 0.993 c? Express your answer with the appropriate un

Keith_Richards [23]

Answer:

(a). The work done is 7001 MeV.

(b). The momentum of this proton is $4.20\times10^{8}\ kg-m/s$ .

Explanation:

Given that,

Speed = 0.993 c

We need to calculate the work done

Using work energy theorem

The work done is equal to the kinetic energy relative to the proton

$W=K.E$

$W=\dfrac{m_{p}c^2}{\sqrt{1-\dfrac{v^2}{c^2}}}-m_{p}c^2$

Put the value into the formula

$W=\dfrac{1.67\times10^{-27}\times(3\times10^{8})^2}{\sqrt{1-(\dfrac{0.993c}{c})^2}}-1.67\times10^{-27}\times(3\times10^{8})^2$

$W=\dfrac{1.67\times10^{-27}\times(3\times10^{8})^2}{\sqrt{1-(0.993)^2}}-1.67\times10^{-27}\times(3\times10^{8})^2$

$W=1.122\times10^{-9}\ J$

$W=7001\ MeV$

(b). We need to calculate the momentum of this proton

Using formula of momentum

$p=\dfrac{m_{0}v}{\sqrt{1-\dfrac{v^2}{c^2}}}$

Put the value into the formula

$p=\dfrac{1.67\times10^{-27}\times0.993c}{\sqrt{1-(\dfrac{0.993c}{c})^2}}$

$p=\dfrac{1.67\times10^{-27}\times0.993c}{\sqrt{1-(0.993)^2}}$

$p=1.404\times10^{-26}c$

$p=4.20\times10^{8}\ kg-m/s$

Hence, (a). The work done is 7001 MeV.

(b). The momentum of this proton is $4.20\times10^{8}\ kg-m/s$ .

4 0

3 years ago

Wondering if you have enough rope to rappel to the ground, you drop a rock off the top, and hear the sound of it hitting the bot

miskamm [114]

Answer:

86.5 m

Explanation:

$s = ut + \frac{1}{2} at {}^{2} \\ s = (0)(4.2) + \frac{1}{2} (9.81)(4.2) {}^{2} \\ s = 86.5m$

4 0

3 years ago

Read 2 more answers

A U-shaped tube open to the air at both ends contains some mercury. A quantity of water is carefully poured into the left arm of

pishuonlain [190]

Answer:

Explanation:

a ) gauge pressure will be due to water column of length 15 cm .

pressure = h d g , h is height of column , d is density of column and g is gravitational acceleration .

= .15 x 10³ x 9.8

= 1470 Pa .

b )

Let due of weight of water column , mercury level in left column goes down by distance h . The level of mercury in right column will rise by the same distance ie by distance h .

So mercury column of 2h height is balancing the water column of height 15 cm

2h x 13.6 x 10³ x g = .15 x 10³ x g

h = .15 / (2 x 13.6)

= .55 x 10⁻² m

= . 55 cm

Difference of height of water column and mercury column

= 15 - 2 x .55 cm

= 13.9 cm .

3 0

3 years ago