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2 years ago

6

If you rearrange the equation so w is the independent variable, then what is u? -2u+6w=9

1 answer:

Serjik [45]2 years ago

7 0

Answer:

u = - ( 9-6w)/2

Step-by-step explanation:

to evaluate for u in the expression -2u+6w=9 is simply to look for a way such that we would express u in terms of w and other variables.

solution

-2u+6w=9

-2u = 9 - 6w

divide both sides by the coefficient of u which is -2

-2u/u = 9 - 6w/-2

u = - ( 9-6w)/2

therefore the value of u when rearranged in the equation -2u+6w=9 is evaluated to be equals to

u = - ( 9-6w)/2

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Carter invested $16,000 in an account paying an interest rate of 5.6% compounded monthly. Assuming no deposits or withdrawals ar

jenyasd209 [6]

Answer:

11 years.

Step-by-step explanation:

Given that Carter invested $ 16,000 in an account paying an interest rate of 5.6% compounded monthly, to determine, assuming no deposits or withdrawals are made, how long would it take, to the nearest year, for the value of the account to reach $ 29,600, the following calculation must be performed:

16,000 x (1 + 0.056 / 12) ^ Yx12 = 29,600

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16,000 x 1.4666 ^ 132 = X

29,581.70 = X

Thus, rounded to the nearest year, it would take 11 years for the account to reach $ 29,600.

8 0

2 years ago

*Find the formula of the series 1+2²+3²+4²+....+n²*<br>

Sophie [7]

The formula is $\frac{n(n+1)(2n+1)}{6}$

What are series?

In mathematics, we can describe a series as adding infinitely many numbers or quantities to a given starting number or amount.

We will find the formula as shown as below:

Let $S=1+2^2+3^2+4^2+................+n^2$

We know $(n+1)^3=n^3+3n^2+3n+1$

$(1+1)^3=1^3+3(1)^2+3(1)+1$

$(2+1)^3=2^3+3(2)^2+3(2)+1$

$(3+1)^3=3^3+3(3)^2+3(3)+1$

.

.

$(n+1)^3=n^3+3(n)^2+3(n)+1$

On adding

$2^3+3^3+4^3......(n+1)^3=(1^3+2^3+3^3+.....+n^3)+3(1^2+2^2+.....+n^2)+3(1+2+3....n)+(1+1+1+....+1)$

$2^3+3^3+4^3......(n+1)^3-(1^3+2^3+3^3+.....+n^3)=3S+\frac{3n(n+1)}{2}+(1+1+1+....+1)$

$(n+1)^3-1^3=3S+\frac{3n(n+1)}{2} +n$

$n^3+3(n)^2+3(n)+1-1=3S+\frac{3n(n+1)}{2} +n$

$2n^3+6n^2+6n=6S+3n^2+3n+2n$

$6S=2n^3+3n^2+n$

$6S=2n^2(n+1)+n(n+1)$

$6S=(n+1)(2n^2+n)$

$6S=n(n+1)(2n+1)$

$S=\frac{n(n+1)(2n+1)}{6}$

Hence, the formula is $\frac{n(n+1)(2n+1)}{6}$

Learn more about Series here:

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3 0

1 year ago

Kristin's credit rating was lowered, and the credit card company raised her APR from 14% to 15.2%. If her average daily balance

Sloan [31]

Answer:

0.0022x

Step-by-step explanation:

Given that,

The credit card company raised her APR from 14% to 15.2%.

Her average daily balance this month is x dollars.

We need to find the algebraically the increase in this month's finance charge due to the higher APR. It can be calculated as follows :

$y=x\times \dfrac{12\%}{14}-x\times \dfrac{15.2\%}{14}\\\\=x\times \dfrac{12}{1400}-x\times \dfrac{15.2}{1400}\\\\=-0.0022x$

So, the required increase in the month's finance is 0.0022x.

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Step-by-step explanation:

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Gnesinka [82]

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Step-by-step explanation:

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3 years ago

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