A parabola is a quadratic function, and a quadratic can be expressed in vertex form, which is:
y=a(x-h)^2+k, where (h,k) is the vertex (absolute maximum or minimum point of the quadratic)
In this case we are given that (h,k) is (-5,80) so we have so far:
y=a(x--5)^2+80
y=a(x+5)^2+80, we are also told that it passes through the point (0,-45) so:
-45=a(0+5)^2+80
-45=25a+80 subtract 80 from both sides
-125=25a divide both sides by 25
-5=a, so now we know the complete vertex form is:
y=-5(x+5)^2+80
The x-intercepts occur when y=0 so:
0=-5(x+5)^2+80 add 5(x+5)^2 to both sides
5(x+5)^2=80 divide both sides by 5
(x+5)^2=16 take the square root of both sides
x+5=±√16 which is
x+5=±4 subtract 5 from both sides
x=-5±4 so the x-intercepts are:
x=-1 and -9
Answer:both are in thousandths place,in the thousandths place both have 4 as a value
Step-by-step explanation:
You would have to do 500x 4 which is 2000
Answer:
5.24, 21/4, or 5 and 1/4
Step-by-step explanation:
78+139+14 = 231
231/44 = 5.25
Or 21/4 (improper fraction)
Or 5 and 1/4 (mixed number)
I'm not exactly sure what you were asking I hope that helps!
Rewriting the formula in standard form would be x^2-8x+14=0
