Answer:
we reject H₀ we have enough evidence to say that tickets are cheaper in secondary market
Step-by-step explanation:
The situatin have to be evaluate with a left tail test
We have Normal Distribution
1.- Hypothesis
H₀ ⇒ μ₀ = 225
Hₐ ⇒ μₐ ≠ 225
2.-Critical values :
We find α = 0.01 and z(c) = - 2.324
3.- z(s) = ( μ - μ₀ ) /( σ/√n) ⇒ z(s) = (207 -225)/ (43/√40)
z(s) = - 18 *√40/ 43 ⇒ z(s) = -113,84/ 43
z(s) = - 2.6474
4.-Evaluation
z(s) < z(c) - 2.64 < - 1.64
z(s) is in rejection zone we reject H₀