3 x + 3 (x + y)
3 (2 x + y)
6 x + 3 y
y = -2 x
y = -2 x (3 (x + y) + 3 x) = 6
(3 (x + y) + 3 x) = 3
(3 x + 3 (x + y)) dx = 3 (x^2 + x y) +
(x^2 + y^2<R^2)(3 (x + y) + 3 x) dx dy = 0
(3 x + 3 (x + y)) dy dx = 0
Step-by-step explanation:
Hope this helps ツ
In f(x) = 16(0.75)x the (0.75) does not have a 1 so it is decreasing and if it is only 75% of 16 then it would be losing 25% each time So the exponential decay will be 25%.
He starts at -184 ft (since he is below the surface) and then goes up + 53 ft putting him at -131 ft.
-184+53=-131
Then he goes down another -168 feet to -299 ft.
-131-168=-299
So, he is currently at -299ft, or 299 feet below the surface.
The radius of <span>(x^2−6x)+(y^2−10y)=−18
is 4
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