The maximum value can be determined by taking the derivative of the function.
(dh/dt) [h(t)] = h'(x) = -9.8t + 6
Set h'(x) = 0 to find the critical point
-9.8t + 6 = 0
-9.8t = -6
t = 6/9.8
Plug the time back into the function to find the height.
h(6/9.8) = -4.9(6/9.8)^2 + 6(6/9.8) + .6
= 2.4
And I don't understand your second question.
Answer:
a) correct option is
Poisson distribution is 6.2 and standard deviation is 2.49
b) probability for only 2 or less than 2 surgeries in a given day is 0.0536
Step-by-step explanation:
Given data:
mean number is given as 6.2
correct option is
Poisson distribution is 6.2 and standard deviation is 2.49
we know that variance is given as
hence, standard deviation is given as 
thus standard deviation is 2.49
correct option is
Poisson distribution is 6.2 and standard deviation is 2.49
b) probability for only 2 or less than 2 surgeries in a given day is


= 0.002029 + 0.012582+ 0.039006
= 0.053617
= 0.0536
A) y= -2, 3, 7
B) y= 8, 0, -6
C) y= -8, 1, 7
d) y= 1, -2, -6
Answer:
Step-by-step explanation:
if we're estimating ,we're going to round up to 8 since you can multiply that easier. 25 times 8 is 200 so estimation will be around 200