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konstantin123 [22]

3 years ago

13

Carmen rolls a cube with sides labeled A, B, C, D, E, and F.

1 answer:

Sav [38]3 years ago

5 0

The number of possible outcomes is 29. ! hope this help hun <3

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Shannon set her watch 3 seconds behind, and it falls behind another 2 seconds everyday. How many days has it been since Shannon

GrogVix [38]

The answer is 32 all you have to do to get you answer is add 3 and 2 which gives you 5 and you add it up until you get to 67 and you have to see how many times you add it up to get the answer which is 3 or a shorter way is 31 times 2 plus 5 and it gives you 67

8 0

3 years ago

Hey can you please help me posted picture of question:)

castortr0y [4]

The given trinomial can be factored using the factorization method.

x² -12x + 35
= x² -7x -5x + 35
= x(x-7) - 5(x-7)
= (x-7)(x-5)

Thus, (x-7)(x-5) is the factored form of the polynomial.

So the correct answer is option B

3 0

4 years ago

The first thing you should do in solving a word problem is estimate what you think the answer would be.

Lelu [443]

Answer:

The answer is True.

Step-by-step explanation:

<u>Estimate the Answer Before Solving Having a general idea of a ballpark answer .</u>
<u>Or the problem lets students know if their actual answer is reasonable or not.</u>

6 0

2 years ago

Find the measure of <1<br> A.) 30<br> B.) 45<br> C.) 15<br> D.) 60

nataly862011 [7]

45 would most likely be right

5 0

3 years ago

Simplify the following

den301095 [7]

Answer:

1) 11 $\sqrt{3}$

2) 2 $\sqrt{2}$

3) $20\sqrt{3} + 15\sqrt{2}$

4) $53 + 12\sqrt{10}$

5) -2

6) $7\sqrt{2} - 5\sqrt{3}$

Step-by-step explanation:

1) 2 $\sqrt{12}$ + 3 $\sqrt{48}$ - $\sqrt{75}$

=(2 × 2 $\sqrt{3}$ )+ (3 × 4 $\sqrt{3}$ ) - 5 $\sqrt{3}$

= 4 $\sqrt{3}$ + 12 $\sqrt{3}$ - 5 $\sqrt{3}$

= 11 $\sqrt{3}$

2) 4 $\sqrt{8}$ -2 $\sqrt{98}$ + $\sqrt{128}$

= (4 × 2 $\sqrt{2}$ ) - (2 × 7 $\sqrt{2}$ ) + 8 $\sqrt{2}$

= 8 $\sqrt{2}$ - 14 $\sqrt{2}$ +8 $\sqrt{2}$

= 2 $\sqrt{2}$

3) 5 $\sqrt{12\\}$ - 3 $\sqrt{18} + 4 \sqrt{72} +2\sqrt{75}$

= 5× $2\sqrt{3}$ - 3× $3\sqrt{2}$ + 4× $6\sqrt{2}$ + 2× $5\sqrt{3}$

= $10\sqrt{3} - 9\sqrt{2} +24\sqrt{2} +10\sqrt{3}$

= $20\sqrt{3} + 15\sqrt{2}$

4) $(2\sqrt{2} + 3\sqrt{5} )^{2}$

= $8 + 12\sqrt{10} + 45$

= $53 + 12\sqrt{10}$

5) $(1+\sqrt{3} ) (1-\sqrt{3} )$

= $1 - 3$

= -2

6) $(2\sqrt{6} -1) (\sqrt{3} -\sqrt{2} )$

= $2\sqrt{18}-2\sqrt{12} -\sqrt{3} +\sqrt{2}$

= 2× $3\sqrt{2}$ - 2× $2\sqrt{3}$ - $\sqrt{3} + \sqrt{2}$

= $6\sqrt{2} - 4\sqrt{3} -\sqrt{3} +\sqrt{2}$

= $7\sqrt{2} - 5\sqrt{3}$

Hope the working out is clear and will help you. :)

5 0

3 years ago

Read 2 more answers