Answer:68.3 degrees
Step-by-step explanation:
The diagram of the triangle ABC is shown in the attached photo. We would determine the length of side AB. It is equal to a. We would apply the cosine rule which is expressed as follows
c^2 = a^2 + b^2 - 2abCos C
Looking at the triangle,
b = 75 miles
a = 80 miles.
Angle ACB = 180 - 42 = 138 degrees. Therefore
c^2 = 80^2 + 75^2 - 2 × 80 × 75Cos 138
c^2 = 6400 + 5625 - 12000Cos 138
c^2 = 6400 + 5625 - 12000 × -0.7431
c^2 = 12025 + 8917.2
c = √20942.2 = 144.7
To determine A, we will apply sine rule
a/SinA = b/SinB = c/SinC. Therefore,
80/SinA = 144.7/Sin 138
80Sin 138 = 144.7 SinA
SinA = 53.528/144.7 = 0.3699
A = 21.7 degrees
Therefore, theta = 90 - 21.7
= 68.3 degees
Answer:
b) 3cd+3 1/3c-3d
Step-by-step explanation:
It can work well to factor the variables out so you can see the coefficients more easily:
6cd+3c-7d-3cd+4d+1/3c
= (6 -3)cd +(3 +1/3)c +(-7 +4)d
= 3cd +(3 1/3)c -3d
Answer:
13
Step-by-step explanation:
It's not 3.25 because if you simplify 6.5 and 0.5, you get 65 and 5 which if you divide is 13.
Answer:
m∠ONP = 43*
m∠LNO = 137*
m∠MNP = 137*
Step-by-step explanation:
Each line segment is a straight line meaning they are each worth 180°, so if you take 43° from 180° you're eft with 137° which is what ∠LNO and ∠MNP are equal to. ∠ONP is 43° since it is a vertical angle to ∠MNL which is also 43°.