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3 years ago

How do you find the pattern of 0,2,6,12,20???

Mathematics

1 answer:

professor190 [17]3 years ago

3 0

0x1=0
1x2=2
2x3=6
3x4=12
4x5=20

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Kim was walking down a rocky path.For 4 minutes, the elevation dropped steadily.All together it dropped 8 feet. What was the cha

fenix001 [56]

Answer:

2 $\frac {{\textrm{feet}}}{{\textrm{minute}}}$

Step-by-step explanation:

Kim was walking down a rocky path. For 4 minutes, the elevation dropped steadily. All together it dropped 8 feet.

So, the change in elevation per minute for the 4 minutes is given by,

$\frac {8}{4} \frac {{\textrm{feet}}}{{\textrm{minute}}}$

= 2 $\frac {{\textrm{feet}}}{{\textrm{minute}}}$

(Answer)

8 0

3 years ago

HELP PICTURE SHOWN!!!!

laila [671]

I hate APEX!

A is right since the graph would start at 2 and go towards negative infinity

D is right both graphs approach +2 as thier highest values

6 0

3 years ago

8. What is the radius of a circle when the

Bezzdna [24]

Answer:

radius = circumference ÷ 2× po

Step-by-step explanation:

the radius is 2.55 but it's not in ur options

7 0

3 years ago

Read 2 more answers

1011+111 in binary form

Ann [662]

Answer:

10010

Step-by-step explanation:

$1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$111=1(2)^2+1(2)^1+1(2)^0$

So $1011+111$ gives us:

$1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$+$

$1(2)^2+1(2)^1+1(2)^0$

-----------------------------------------------------

Combine like terms:

$1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0$

$1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0$

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace $2^0$ with 1 and $2$ with $(2)^1$ :

$1(2)^3+1(2)^2+(2)^2+(2)^1(1)$

I want a $2^0$ number:

$1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0$

Combine like terms:

$1(2)^3+2(2)^2+1(2)^1+0(2)^0$

$2(2)^2=2^3$ :

$1(2)^3+2^3+1(2)^1+0(2)^0$

Combine like terms:

$2(2)^3+1(2)^1+0(2)^0$

We can rewrite the first term by law of exponents:

$2^4+1(2)^1+0(2)^0$

$1(2)^4+1(2)^1+0(2)^0$

So the binary form is:

$10010$

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

1 0 1 1

+ 1 1 1

------------------------------

(1) (1) (1)

1 0 1 1

+ 1 1 1

------------------------------

1 0 0 1 0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0

3 years ago

Plz help with question 10

Sophie [7]

I believe D is correct

8 0

3 years ago