Answer:
P=0.147
Step-by-step explanation:
As we know 80% of the trucks have good brakes. That means that probability the 1 randomly selected truck has good brakes is P(good brakes)=0.8 . So the probability that 1 randomly selected truck has bad brakes Q(bad brakes)=1-0.8-0.2
We have to find the probability, that at least 9 trucks from 16 have good brakes, however fewer than 12 trucks from 16 have good brakes. That actually means the the number of trucks with good brakes has to be 9, 10 or 11 trucks from 16.
We have to find the probability of each event (9, 10 or 11 trucks from 16 will pass the inspection) . To find the required probability 3 mentioned probabilitie have to be summarized.
So P(9/16 )= C16 9 * P(good brakes)^9*Q(bad brakes)^7
P(9/16 )= 16!/9!/7!*0.8^9*0.2^7= 11*13*5*16*0.8^9*0.2^7=approx 0.02
P(10/16)=16!/10!/6!*0.8^10*0.2^6=11*13*7*0.8^10*0.2^6=approx 0.007
P(11/16)=16!/11!/5!*0.8^11*0.2^5=13*21*16*0.8^11*0.2^5=approx 0.12
P(9≤x<12)=P(9/16)+P(10/16)+P(11/16)=0.02+0.007+0.12=0.147
Percent (%) = per 100
7 1/5 = 36/5 = 720/100 = 720%
|4-24x|=52
24x=56
2.333~ is your answer
Answer:
13t² + 2t + 9
Step-by-step explanation:
(9t² - 3t + 5) - (-4t² + 5t + 4)
Solving like terms
-(-4t²) becomes + 4t²
(9t² + 4t²) + (-3t + 5t) + (5+4) =
13t² + 2t + 9
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-Chetan K
Answer:
I suppose the answer would be 120
Step-by-step explanation:
Well if 90 is 75% then 50% should be 60 and 25% should be 30.
so its going up and down by 30, so that would make 100% 120
please give brainliest