Will give 15 points.

Suppose you have a car with a battery that applies 12.5 V to the starter.

Marat540 [252]

Answer:

R = 0.1 ohms

Explanation:

It is given that,

Voltage of the battery, V = 12.5 V

Current flowing in the car's starter, I = 125 A

We need to find the effective resistance of a car's starter. It can be calculated using Ohm's law. Let R is the resistance.

$V=IR\\\\R=\dfrac{V}{I}\\\\R=\dfrac{12.5}{125}\\\\R=0.1\ \Omega$

So, the resistance of the car's starter is 0.1 ohms.

7 0

3 years ago

A spaceship is traveling through deep space towards a space station and needs to make a course correction to go around a nebula.

expeople1 [14]

Answer:

Magnitude = 3.64 × $10^6$

စ = 43.9°

Explanation:

given data

ship to travel = 1.7 × $10^6$ kilometers

turn = 70°

travel an additional = 2.7 × $10^6$ kilometers

solution

we will consider here

Px = 1.7 × $10^6$

Py = 0

Qx =2.7 × $10^6$ cos(70)

Qy= 2.7 × $10^6$ sin(70)

so that

Hx = Px + Qx ............1

Hx = 2.62 × $10^6$

and

Hy = Py + Qy ..........2

Hy = 2.53 × $10^6$

so Magnitude = $\sqrt{((2.62 \times 10^6 )^2+(2.53 \times 10^6)^2)}$

Magnitude = 3.64 ×

so direction will be

tan စ = Hy ÷ Hx ......................3

tan စ = $\frac{2.53}{2.62}$

tan စ = 0.9656

စ = 43.9°

3 0

3 years ago

A simple Atwood’s machine uses a massless

Lady bird [3.3K]

The Atwood's machine is in motion starting from rest, then Vf = Vo + a(t).
Final Velocity is given as 6.7 m/s and the time is 1.9 s thus 6.7= 0+ a(1.9) 
then a = 6.7/1.9 = 3.526 m/s². 
The Atwood's Machine also has the formula d= distance = 1/2a(t²) 
distance given is 6.365 m , then 6.365 = 1/2 a (1.9)², 
a = 3.526 m/s² the same acceleration. 
a= g(m1-m2) / m1+m2) 
m1a + m2a = m1g - m2g 
m1a - m1g = -m2g - m2a 
3.526 m1 - 9.81 m1 = -9.81m2 - 3.526 m2 
-6.28 m1 = -13.34 m2 
0.47 m1= m2 
if 24J = 1/2mv² 
then 24J = 1/2 m1 ( 6.7)² 
48/ 44.89 = m1 
1.069 kg = m1 , then 
0.47(1.069) = m2 
0.503 kg = m2

6 0

4 years ago

Describe and apply Newton’s Three Laws

Maurinko [17]

Newton's First Law of Motion: I. Every object in a state of uniform motion tends to remain in that state of motion unless an external force is applied to it. This we recognize as essentially Galileo's concept of inertia, and this is often termed simply the "Law of Inertia".

5 0

3 years ago

An electron of mass 9.11 x 10^-31 kg has an initial speed of 4.00 x 10^5 m/s. It travels in a straight line, and its speed incre

yarga [219]

Answer:

a. F = 2.32*10^-18 N

b. The force F is 2.59*10^11 times the weight of the electron

Explanation:

a. In order to calculate the magnitude of the force exerted on the electron you first calculate the acceleration of the electron, by using the following formula:

$v^2=v_o^2+2ax$ (1)