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juin [17]
3 years ago
7

Problem 21-40a:

Physics
1 answer:
Greeley [361]3 years ago
8 0

Answer:

Part a)

\frac{F_e}{F_g} = 2.74 \times 10^{12}

Part b)

q = 3.37 \times 10^{-4} C

Explanation:

As we know that electric force on electric charge is given as

F = qE

here we have

q = 1.6 \times 10^{-19}C

E = 153 N/C

now force is given as

F = (1.6 \times 10^{-19})(153) = 2.45 \times 10^{-17} N

Gravitational force on electric charge near surface of earth is given as

F_g = mg

F_g = (9.1 \times 10^{-31})(9.81) = 8.93 \times 10^[-30} N

now the ratio of two forces is given as

\frac{F_e}{F_g} = \frac{2.45 \times 10^{-17}}{8.93 \times 10^{-30}}

\frac{F_e}{F_g} = 2.74 \times 10^{12}

Part b)

Now the ball is balanced by the electric force and the force of gravity on it

so here we have

F_g = qE

mg = qE

(5.25 \times 10^{-3})(9.81) = q(153)

here we have

q = 3.37 \times 10^{-4} C

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nikitadnepr [17]

Answer:

<h3>The answer is 3.0 m/s²</h3>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

a =  \frac{v}{t}  \\

where

a is the acceleration

v is the velocity

t is the time

From the question

v = 12 m/s

t = 4 s

We have

a =  \frac{12}{4}  \\

We have the final answer as

<h3>3.0 m/s²</h3>

Hope this helps you

7 0
3 years ago
Magnetic resonance imaging needs a magnetic field strength of 1.5 T. The solenoid is 1.8 m long and 75 cm in diameter. It is tig
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Answer:

The current needed is 1790.26 A

Explanation:

Given;

magnitude of magnetic field, B = 1.5 T

length of the solenoid, L = 1.8 m

diameter of the solenoid, d = 75 cm = 0.75 m

The magnetic field is given by;

B = \frac{\mu_o NI }{L}

Where;

μ₀ is permeability of free space = 4π x 10⁻⁷ m/A

I is current in the solenoid

N is the number of turns, calculated as;

N = \frac{Length \ of\ solenoid}{diameter \ of \ wire} \\\\N = \frac{1.8}{1.5*10^{-3}} =1200 \ turns

The current needed is calculated as;

I = \frac{BL}{\mu_o N} \\\\I = \frac{1.5 *1.8}{4\pi *10^{-7} *1200} \\\\I = 1790.26 \ A

Therefore, the current needed is 1790.26 A.

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3 years ago
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0.24

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3 years ago
As an admirer of Thomas Young, you perform a double-slit experiment in his honor. You set your slits 1.15 mm apart and position
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Answer:

The distance of the first bright fringe is given as  Y_C = 1.22 *10^{-3}m

The distance of the second dark fringe from the central bright fringe is given as  Y_D = 0.00192 \ m

Explanation:

From the question we are told that

     The slit separation distance is  d = 1.15 mm = \frac{1.15}{1000} =0.00115 m

      The distance of the slit from the screen is  D = 3.23 m

        The wavelength is \lambda  = 633 nm

For constructive interference to occur the distance between the two slit is mathematically represented as

            Y_C  =\frac{m \lambda D}{d}

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               Y_C = \frac{1 * 633 *0^{-9} * 3.23}{0.00115}

                Y_C = 1.22 *10^{-3}m

For destructive  interference to occur the distance between the two slit is mathematically represented as

            Y_D  =  [n + \frac{1}{2} ] \frac{\lambda D}{d}

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so the formula to get the dark fringe is n = \frac{1}{2} * 1

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                   Y_D =1.5 * \frac{633 *10^{-9} * 3.23 }{0.00115}

                        Y_D = 0.00192 \ m

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