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baherus [9]
3 years ago
6

Suppose you have a car with a battery that applies 12.5 V to the starter.

Physics
1 answer:
Marat540 [252]3 years ago
7 0

Answer:

R = 0.1 ohms

Explanation:

It is given that,

Voltage of the battery, V = 12.5 V

Current flowing in the car's starter, I = 125 A

We need to find the effective resistance of a car's starter. It can be calculated using Ohm's law. Let R is the resistance.

V=IR\\\\R=\dfrac{V}{I}\\\\R=\dfrac{12.5}{125}\\\\R=0.1\ \Omega

So, the resistance of the car's starter is 0.1 ohms.

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A ball is ejected to the right with an unknown horizontal velocity from the top of a pillar that is 50 meters in height. At the
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Answer:

15.67 m/s

Explanation:

The ball has a projectile motion, with a horizontal uniform motion with constant speed and a vertical accelerated motion with constant acceleration g=9.8 m/s^2 downward.

Let's consider the vertical motion only first: the vertical distance covered by the ball, which is S=50 m, is given by

S=\frac{1}{2}gt^2

where t is the time of the fall. Substituting S=50 m and re-arranging the equation, we can find t:

t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2(50 m)}{9.8 m/s^2}}=3.19 s

Now we now that the ball must cover a distance of 50 meters horizontally during this time, in order to fall inside the carriage; therefore, the velocity of the carriage should be:

v=\frac{d}{t}=\frac{50 m}{3.19 s}=15.67 m/s

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3 years ago
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Answer:

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