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baherus [9]
2 years ago
6

Suppose you have a car with a battery that applies 12.5 V to the starter.

Physics
1 answer:
Marat540 [252]2 years ago
7 0

Answer:

R = 0.1 ohms

Explanation:

It is given that,

Voltage of the battery, V = 12.5 V

Current flowing in the car's starter, I = 125 A

We need to find the effective resistance of a car's starter. It can be calculated using Ohm's law. Let R is the resistance.

V=IR\\\\R=\dfrac{V}{I}\\\\R=\dfrac{12.5}{125}\\\\R=0.1\ \Omega

So, the resistance of the car's starter is 0.1 ohms.

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If you free the cork in a highly pressurized champagne bottle, the resulting launch of the cork will, in principle, cause the bo
Rudiy27

Answer:

6.7 × 10^{-2}

Explanation:

Initial P = Final P

(1.8 × 0) + (.0075 × 0) = (1.8 × x) + (.0075 × 16)

-.12 + 1.8x

x = .0067

5 0
2 years ago
food product with 10 kg mass is being transported to thesurface of the moon,where the acceleration due to gravity is1.624 m/s2;
larisa [96]

Answer:

In SI units 98.1 N, 16.24 N

English units 22.053861 lbf, 3.6509144 lbf

Explanation:

g = Acceleration due to gravity

m = Mass = 10 kg

Weight on Earth

W=mg\\\Rightarrow W=10\times 9.81\\\Rightarrow W=98.1\ N

Converting to lbf

98.1\times 0.22481=22.053861\ lbf

On Moon

W=10\times 1.624\\\Rightarrow W=16.24\ N

Converting to lbf

16.24\times 0.22481=3.6509144\ lbf

In SI units 98.1 N, 16.24 N

English units 22.053861 lbf, 3.6509144 lbf

5 0
2 years ago
Is 40,000 °C hotter or colder than 3,600 °C????
Amiraneli [1.4K]
Yes because if 0*c equals 32*F than the higher the number the hotter it is
4 0
3 years ago
Read 2 more answers
a bubble of air of volume 1cm^3 is released by a deep sea diver at a depth where the pressure is 4.0 atmospheres. assuming its t
lys-0071 [83]

Answer:

hope this helps!

Explanation:

Volume of the air bubble, V1=1.0cm3=1.0×10−6m3

Bubble rises to height, d=40m

Temperature at a depth of 40 m, T1=12oC=285K

Temperature at the surface of the lake, T2=35oC=308K

The pressure on the surface of the lake: P2=1atm=1×1.103×105Pa 

The pressure at the depth of 40 m: P1=1atm+dρg

Where,

ρ is the density of water =103kg/m3

g is the acceleration due to gravity =9.8m/s2

∴P1=1.103×105+40×103×9.8=493300Pa

We have T1P1V1=T2P2V2

Where, V2 is the volume of the air bubble when it reaches the surface.

V2=

8 0
2 years ago
According to Newton's Second Law, the force of the club hitting the golf ball will cause it to accelerate. At the moment of impa
vazorg [7]

Answer:

Option B

Explanation:

<h3>According to Newton's third law, for every reaction there will be equal and opposite reaction</h3>

Here in this case the force of the club hitting the golf ball will be in one direction and the force acting on club due to golf ball will be in opposite direction and magnitude of this force will be same as the magnitude of the force of the club hitting the golf ball

In this case the action will be the force of the club hitting the golf ball and reaction will be the force acting on club due to golf ball

∴ The club pushes against to golf ball with a force equal and opposite to the force of the golf ball on the club  

8 0
3 years ago
Read 2 more answers
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