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AlexFokin [52]
3 years ago
14

Kathy takes her cat to a veterinarian every year for a check-up. Last year, the difference in the cat's weight from teh year bef

ore was -1.56 pounds. This year, the difference in its weight form last year is 0.73 pounds. What is the difference in the cat's weight from 2 years ago?
Mathematics
1 answer:
Nataliya [291]3 years ago
3 0
To find the difference in weights from two years ago, you will need to combine the 2 differences from the two years.  

-1.56 and 0.73 becomes -1.56 + 0.73.

To add a positive and a negative number you will subtract the absolute values of the numbers AND use the sign of the number with the bigger absolute value (negative) in your answer.

|-1.56| - |0.73|
1.56 - 0.73 = 0.83
-0.83

The cat lost 0.83 (-0.83) pounds over 2 years.
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Which relationship describes angles 1 and 2?
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vertical angles

Step-by-step explanation:

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the amount increased by approximatley 12%

Step-by-step explanation:

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4. Two points on a line are (-10, 1) and (5, -5). If
Vsevolod [243]

Answer:

The x-coordinate of another point is zero

Step-by-step explanation:

step 1

Find the slope between the two given points

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have

(-10,1),(5,-5)

substitute in the formula

m=\frac{-5-1}{5+10}

m=\frac{-6}{15}

Simplify

m=-\frac{2}{5}

step 2

Find the x-coordinate of another point

we have

(x,-3)

we know that

If the other point is on the line, then the slope between the other point and any of the other two points must be the same

so

Find the slope between the points

(x,-3),(5,-5)

Remember that

m=-\frac{2}{5}

substitute in the formula

-\frac{2}{5}=\frac{-5+3}{5-x}

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the denominators must be the same

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The x-coordinate of another point is zero

3 0
3 years ago
Deer ticks can be carriers of either Lyme disease or human granulocytic ehrlichiosis (HGE). Based on a recent study, suppose tha
san4es73 [151]

Answer:

0.2364

Step-by-step explanation:

We will take

Lyme = L

HGE = H

P(L) = 16% = 0.16

P(H) = 10% = 0.10

P(L ∩ H) = 0.10 x p(L U H)

Using the addition theorem

P(L U H) = p(L) + P(H) - P(L ∩ H)

P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)

P(L U H) = 0.26 - 0.10p(L u H)

We collect like terms

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This can be rewritten as:

P(L U H)[1 +0.1] = 0.26

Then we have,

1.1p(L U H) = 0.26

We divide through by 1.1

P(L U H) = 0.26/1.1

= 0.2364

Therefore

P(L ∩ H) = 0.10 x 0.2364

The probability of tick also carrying lyme disease

P(L|H) = p(L ∩ H)/P(H)

= 0.1x0.2364/0.1

= 0.2364

3 0
2 years ago
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