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kari74 [83]
3 years ago
15

A certain disease has an incidence rate of 0.2%. If the false negative rate is 8% and the false positive rate is 4%, compute the

probability that a person who tests positive actually has the disease.
Mathematics
1 answer:
alexira [117]3 years ago
7 0

Answer:

32%

Step-by-step explanation:

Imagine 100000 people are tested.  

<u>Of these 100000:</u>

  • 10000080.02= 2000 will have the disease

<u>8% of them:</u>

  • 2000*0.08= or 160, will test negative and the remaining
  • 1840 will test positive.  

<u>Of the 98000 who do not have the disease, 4% will test positive:</u>

  • 98000*0.04= 3920 will test positive

<u>So of the:</u>

  • 1840+3920= 5760 total people who test positive,
  • 1840 will have the disease

<u>Thus, the probability is: </u>

  • 1840/​5760 ​​ ≈0.3194 = 32%

So, out of people who test positive actually 32% has the disease.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Square root of 8 over 2 is about 1.41 which makes it the least value

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A 3-column table with 4 rows. Column 1 is labeled Inequality with entries 6 greater-than 4, negative 11 less-than negative 3, 7
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At Prairieview Middle School, 100 students participate in at least one of three after-school clubs: soccer club, art club, and g
Tresset [83]

Answer:

17

Step-by-step explanation:

Number of students in soccer club, n(S) = 50

Number of students in Art club, n(A) = 53

Number of students in Gaming club, n(G)

n(S \cup A\cup G) = 100

n(S \cap A\cap G) = 9

n(S \cap A) = 20

n(A \cap G) = 35

n(G \cap S) = 29

Formula:

n ( A ∪ B ∪ C ) =  n(A) + n(B) + n(C) – n ( A ∩ B ) – n(B ∩ C) – n (A ∩ C) + n( A ∩ B ∩ C )

Putting the values:

100 = 50 + 53 + n(G) - 20 - 35 - 29 + 9

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Number of students in gaming club only = n(G) - n(G \cap S) - n(A \cap G) + n(S \cap A\cap G)

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3 years ago
Multiplying Powers with the Same Base
Luda [366]

Applying the product rule of exponents, each product of powers are matched with its simplified expression as:

1. 5 \times 5^3 = 5^4

2. 5 \times 5^3 = 5^4

3. 5^{-3} \times 5^{-3} = \frac{1}{5^6}

4. 5^{-4} \times 5^{4} \times 5^0 = 5^0

5. 5^{7} \times 5^{3} = 5^{10}

To multiply the powers having the same base, we will apply the product rule for exponents.

<h3>What is the Product Rule for Exponents?</h3>
  • Base on the product rule for exponents, we have, a^m \times a^n = a^{m + n} = a^{mn}.
  • In order to find the products of two given numbers that have the same base, the exponents would be added together.

1. 5^6 \times 5^{-4

Add the exponents together

5^6 \times 5^{-4} = 5^{(6) + (-4)}

5^6 \times 5^{-4} = 5^2

2. 5 \times 5^3

Add the exponents together

5 \times 5^3 = 5^{(1 + 3)}

5 \times 5^3 = 5^4

3. 5^{-3} \times 5^{-3}

Add the exponents together

5^{-3} \times 5^{-3} = 5^{(-3) + (-3)

5^{-3} \times 5^{-3} = 5^{-6

5^{-3} \times 5^{-3} = \frac{1}{5^6}

4. 5^{-4} \times 5^{4} \times 5^0

Add the exponents together

5^{-4} \times 5^{4} \times 5^0 = 5^{(-4) + (4) + (0)

5^{-4} \times 5^{4} \times 5^0 = 5^0

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Add the exponents together

5^{7} \times 5^{3} = 5^{10}

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5. 5^{7} \times 5^{3} = 5^{10}

Learn more about product rule of exponents on:

brainly.com/question/847241

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