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olchik [2.2K]
3 years ago
6

PLEASE HELP ASAP!!! 75 POINTS AND BRAINLIEST!!!

Mathematics
1 answer:
antoniya [11.8K]3 years ago
4 0
The average rate of each is 12 because if you calculate the slope of the points it equals 12.

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Which function has a greater rate of change? Function A: x 1.5 2.5 3.5 4.5 5.5 y 5 0 –5 –10 –15 Function B: y = –4.5x + 15 Funct
expeople1 [14]

Answer:

Function A has a rate of change of -5 and Function B has a rate of change of -4.5, so Function B has a greater rate of

Step-by-step explanation:

Function A:

\begin{array}{cccccc}x & {1.5} & {2.5} & {3.5} & {4.5} & {5.5} \ \\ y & {5} & {0} & {-5} & {-10} & {-15} \ \end{array}

Function B:

y = -4.5x + 15

Required

Which has a greater rate of change

The rate of change of function A is calculated as thus:

m = \frac{y_2 - y_1}{x_2 - x_1}

Where:

(x_1,y_1) = (1.5,5)

(x_2,y_2) = (2.5,0)

So, we have:

m = \frac{0-5}{2.5 - 1.5}

m = \frac{-5}{1}

m = -5

For function B

The general function is:

y = mx + b

Where

m is the rate of change

By comparing y = mx + b to y = -4.5x + 15

m = -4.5

So, we have that:

Function A has a rate of -5; function B has a rate of -4.5.

By comparison: -4.5 is greater than 5

Hence, function B has a greater rate.

4 0
3 years ago
What is this me don't get it
Montano1993 [528]
For step b. would be 44 divided by 19 = b for step c you can answwer seeing i gave you the equation and along with question a do things you know first then you might have the answers for the rest i hope this helps 
5 0
3 years ago
Read 2 more answers
Someone help me out please
uysha [10]

1 step (B): raise both sides of the equation to the power of 2.

(\sqrt{x+3}-\sqrt{2x-1})^2=(-2)^2,\\   (x+3)-2\sqrt{x+3}\cdot \sqrt{2x-1}+(2x-1)=4,\\ 3x+2-2\sqrt{x+3}\cdot \sqrt{2x-1}=4.

2 step (A): simplify to obtain the final radical term on one side of the equation.

-2\sqrt{x+3}\cdot \sqrt{2x-1}=4-3x-2,\\ -2\sqrt{x+3}\cdot \sqrt{2x-1}=2-3x,\\ 2\sqrt{x+3}\cdot \sqrt{2x-1}=3x-2.

3 step (F): raise both sides of the equation to the power of 2 again.

(2\sqrt{x+3}\cdot \sqrt{2x-1})^2=(3x-2)^2,\\ 4(x+3)(2x-1)=(3x-2)^2.

4 step (E): simplify to get a quadratic equation.

4(2x^2-x+6x-3)=(3x)^2-2\cdot 3x\cdot 2+2^2,\\ 8x^2+20x-12=9x^2-12x+4,\\ x^2-32x+16=0.

5 step (D): use the quadratic formula to find the values of x.

D=(-32)^2-4\cdot 16=1024-64=960, \\ \sqrt{D} =8\sqrt{5} ,\\ x_{1,2}=\dfrac{32\pm 8\sqrt{5}}{2} =16\pm 4\sqrt{5}.

6 step (C): apply the zero product rule.

x^2-32x+16=(x-16-4\sqrt{5}) (x-16+4\sqrt{5}) ,\\ (x-16-4\sqrt{5}) (x-16+4\sqrt{5}) =0,\\ x_1=16+4\sqrt{5} ,x_2=16-4\sqrt{5}.

Additional 7 step: check these solutions, substituting into the initial equation.

3 0
3 years ago
Solve for x:<br> (X+1)(x-3) = 0
Anton [14]

Answer:


Step-by-step explanation:

x= -1 or x=3

8 0
3 years ago
In what form is the following linear equation written?
krek1111 [17]
Answer is B standard
3 0
3 years ago
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