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Damm [24]
3 years ago
9

Olivia has developed a great presentation with a distinct purpose and excellent content. She delivered it in a workshop and got

great feedback on the evaluation form. Because she did such a good job, she intends to use the exact same presentation for the panel discussion she will be in next week. Her coworker has advised against this because _____.
1.a clear central message is not needed for panel discussions
2.less time and depth is required for panel discussions
3.panel discussions require the use of additional special effects
4.workshop presentations need bullet points; panel discussions do not
Computers and Technology
1 answer:
Umnica [9.8K]3 years ago
3 0

less time and depth is required for panel discussions

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Determine which careers you can enter after completing a training program and which careers require a college degree.
KonstantinChe [14]

Answer: statistician automotive engineer customer service specialist data modeler broadcast technician video systems technician

Explanation:

8 0
2 years ago
A network administrator notices that some newly installed Ethernet cabling is carrying corrupt and distorted data signals. The n
MakcuM [25]

A network administrator notices that some newly installed Ethernet cabling is carrying corrupt and distorted data signals. The new cabling was installed in the ceiling close to fluorescent lights and electrical equipment

Two factors may interfere with the copper cabling and result in signal distortion and data corruption are :

EMI

RFI

Explanation:

  • EMI (electromagnetic interference) is the disruption of operation of an electronic device when it is in the vicinity of an electromagnetic field (EM field) in the radio frequency (RF) spectrum that is caused by another electronic device.
  • During EMC testing, radiated emissions measurements are made using a spectrum analyzer and or an EMI receiver and a suitable measuring antenna.
  • EMI (Electromagnetic Interference) is also called RFI (Radio Frequency Interference).
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3 0
3 years ago
Question 4. Use simulate_several_key_strikes 1000 times, each time simulating the monkey striking 11 keys. Compute the proportio
Arisa [49]

Answer:

Chech the explanation

Explanation:

<em>In [16]:</em>

<em />

# Your answer to this question might be written on more than a line.

datascience_trials = make_array()

for  i  in np.arange(1000):

            datascience_trials = np.append(datascience_trials, simulate_several_key_strikes(1))

datascience_proportion = np.count_nonzero(datascience_trials == 'datascience')/1000

datascience_proportion

<em>Out [16]:</em>

0.0

<em>In [17]:</em>

_ = ok.grade('q2_4')

````````````````````````````````````````````````````````````````````````````````````````````````````````

#Running tests

4 0
3 years ago
The ____________ is an interest inventory that classifies people according to six different types: Realistic, Investigative, Art
Kamila [148]
1) C) Campbell Interest Inventory.

Also known as the Strong Interest Inventory, this was developed based on the Holland Codes (6 traits listed in the question), it was developed by psychiatrist Edward Strong and later revised by David Campbell. 

2) C) FOCUS2

The FOCUS2 test is a test that matches students with study programs based on their assessed aptitudes and interests. <span />
7 0
3 years ago
Read 2 more answers
Suppose you wish to develop a matrix-multiplication algorithm that is asymptotically faster than Strassen’s algorithm. Your algo
Kazeer [188]

Answer:

The number of subproblems are given as T(n)=a*T(n/8)+\theta(n^2) while the value of T(n) to be less than S(n) is for 342.

Explanation:

The number of subproblems are given as

T(n)=a*T(n/8)+\theta(n^2)

Asymptotic running time for Strassen’s algorithm is S(n)=\theta(n^{log(7)})

Now, when a increases, number of subproblems determines the asymptotic running time of the problem and case 1 of master theorem applies. So, in worst case, asymptotic running time of the algorithm will be

T(n)=\theta(n^{logb(a)})=\theta(n^{log8(a)})=\theta(n^{log_{2}(a^{1/3})})

Now, for T(n) to be smaller than S(n)

n^{loga^{1/3}}

So,

log(a^{(1/3)})

So,

a=342

5 0
3 years ago
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