Question

Light whose wavelength is 565 is incident on a 0.00600 wide slit. At what angle is the first diffraction minimum located??

Answer 1

The first diffraction minimum located at an angle of 5.40°.

Explanation:

Here the wavelength, λ = 565 nm = 565 × 10⁻⁹ m

Width of the slit, d = 0.00600 mm = 6 × 10⁻⁶ m

We need to find the angle as,

sin θ = mλ / d

We have to find the angle as,

θ  = sin⁻¹ ( mλ / d )

Here m = 1,

θ = sin⁻¹ ( $\frac{1\times565 \times 10^{-9} }{6\times 10^{-6} }$ )

  = sin⁻¹(0.0942)

  = 5.40°

So the first diffraction minimum located at an angle of 5.40°.