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4 years ago

Light whose wavelength is 565 is incident on a 0.00600 wide slit. At what angle is the first diffraction minimum located??

Computers and Technology

1 answer:

yanalaym [24]4 years ago

5 0

The first diffraction minimum located at an angle of 5.40°.

Explanation:

Here the wavelength, λ = 565 nm = 565 × 10⁻⁹ m

Width of the slit, d = 0.00600 mm = 6 × 10⁻⁶ m

We need to find the angle as,

sin θ = mλ / d

We have to find the angle as,

θ = sin⁻¹ ( mλ / d )

Here m = 1,

θ = sin⁻¹ ( $$\frac{1\times565 \times 10^{-9} }{6\times 10^{-6} }$ )

= sin⁻¹(0.0942)

= 5.40°

So the first diffraction minimum located at an angle of 5.40°.

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1 year ago

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Answer:

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#include <fstream>

using namespace std;

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}

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3 years ago

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Answer:

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