Answer:
The correct answer to the following question is Drive-by hacking
.
Explanation:
Drive-by hacking is the type of hacking which comes under the cyberterrorism.
Drive-by hacking is the hacking where the hackers can access their data and steal their data, use their network services from some "safe" distance without going inside the company or an organization.
Drive-by download is the type of download of the malicious code into your mobile devices or the computers which occur by designed and it leave you to the cyberattack.
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.
public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}
So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.
A quick explanation:
We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.
The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.
Answer:
The answer is hybrid computer coz it is the combination of both analog and digital computers
Explanation:
hope it helps
good day
Answer:
DDR
Explanation:
DDR is a feature of memory. It means a double data rate and is a more sophisticated version of the SDRAM, which is a memory. And the rest like the Multicore, 64-bit processing, and the L1 cache are the features of the CPU. And hence, the correct option here is none other than DDR. Remember that the L1 cache is the memory bank, which is being built over the CPU chip. And we have 32 bit and 64-bit processing for the CPU. As well as CPU can be dual-core, quad-core and likewise.
