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Margaret [11]
3 years ago
7

Another question: r = ab/a+b Find a....

Mathematics
2 answers:
AnnyKZ [126]3 years ago
8 0
I think the answer is br/b-r = a 
MArishka [77]3 years ago
4 0
Keep in mind, because they didn't give us any values we can only find what a equals in terms of the other variables. You'll see what I mean after we get to the final answer. 

r = (ab)/(a+b)

Multiply both sides by (a+b)

r(a+b) = (ab)

Divide by r on both sides. 

(a+b) = (ab)/r

Subtract b on both sides. 

a = ((ab)/r) - b 

You can't simplify it any further to my knowledge. Well, besides getting a common denominator with b and subtracting them, but it won't really simplify things. 

Now. Let's get a better answer... haha. Here we go: 

r = (ab)/(a+b) 

Same step. Multiply on both sides. 

r(a+b) = (ab)

This time distribute the r to all values. 

ar + br = (ab)

Subtract ar on both sides. 

ar + br - ar = ab - ar

br = ab - ar

Next step! Factor "a" out of ab - ar by making it a quantity time "a" with "a" removed...
it's easier to show than to explain. So here you go: 

br = a(b - r) 

Divide (b - r) on both sides. 

(br)/(b-r) = a

Hope that helped some! :p 
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An object is launched from a launching pad 144 ft. above the ground at a velocity of 128ft/sec. what is the maximum height reach
ollegr [7]

Answer:

18) a. h(x) = -16x² + vx + h(0) ⇒ h(x) = -16x² + 128x + 144

b. The maximum height = 400 feet

c. Attached graph

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* Lets study the rule of motion for an object with constant acceleration

# The distance S = ut ± 1/2 at², where u is the initial velocity, t is the time

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18)a.

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   of the motion

  is upward

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* Find the height of the object after x seconds from the ground

∵ h(0) = 144 and v = 128 ft/sec

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b.

* At the maximum height h'(x) = 0

∵ h'(x) = -32x + 128

∴ -32x + 128 = 0 ⇒ subtract 128 from both sides

∴ -32x = -128 ⇒ ÷ -32

∴ x = 4 seconds

- The time for the maximum height = 4 seconds

- Substitute this value of x in the equation of h(x)

∴ The maximum height = -16(4)² + 128(4) + 144 = 400 feet

c. Attached graph

19)

- The object will reach the maximum height after 4 seconds

20)

- When the rocket hits the ground h(x) = 0

∵ h(x) = -16x² + 128x + 144

∴ 0 = -16x² + 128x + 144 ⇒ divide the two sides by -16

∴ x² - 8x - 9 = 0 ⇒ use the factorization to find the value of x

∵ x² - 8x - 9 = 0

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∴ x - 9 = 0 OR x + 1 = 0

∴ x = 9 OR x = -1

- We will rejected -1 because there is no -ve value for the time

* The time for the object to hit the ground is 9 seconds

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