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KatRina [158]
3 years ago
14

Lauren brings brownies to class one day. She gives 3/5 of them to her friends Gareth, tammy, and Camila. If she gave them 21 bro

wnies, how many did she bring to class?
Mathematics
1 answer:
Keith_Richards [23]3 years ago
8 0
Answer : 35 brownies
==================================
working:

3/5 = 21
1/5 = 21 / 3
1/5 = 7
5/5 = 7 x 5
1 (the amount of brownies she brought) = 35

Therefore, she brought 35 brownies
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Paul went on a bike ride of 30 miles. He realized that if he had gone 8 mph faster, he would have arrived 12 hours sooner. How f
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Answer: He actually rode 2 miles per hour on his trip

Step-by-step explanation: Maybe unconventional, but express the time it took, then figure the speed.

Time  = distance /speed  t will represent time, s is the speed:  t = 30/s Use the rime it would have taken at the higher speed to create an equation:

t-12 = 30/s+8   replace the y with the 30/s

30/s -12 = 30/s+8

(s)(30/s -12 ) = (s)(30/s+8 )  Cross multiply to cancel denominators  

(s-8)(30 -12s) = (s-8)(30s/s+8 ) ==> 30s +240 -12s² -96s =30s   Simplify:  

(-1)(-12s² -96s +240 ) =0 ==>  12s² +96s -240  divide all by 12

s² + 8s -20 = 0   Factor and solve for s

(s +10)(s -2) =0    s-2=0   S= 2  

Proof:

30/2 = 15 hours for original trip at 2mph,  

increase speed by 8mph   2 + 8 = 10mph

30 miles at 10mph takes 3 hours; that is 12 hours less than his actual trip.

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Answer:

a. The positive difference between Nelson's height and the population mean is: \\ \lvert 68-70.7 \rvert = \lvert 70.7-68 \rvert\;in = 2.7\;in.

b. The difference found in part (a) is 1.174 standard deviations from the mean (without taking into account if the height is above or below the mean).

c. Nelson's z-score: \\ z = -1.1739 \approx -1.174 (Nelson's height is <em>below</em> the population's mean 1.174 standard deviations units).

d. Nelson's height is <em>usual</em> since \\ -2 < -1.174 < 2.

Step-by-step explanation:

The key concept to answer this question is the z-score. A <em>z-score</em> "tells us" the distance from the population's mean of a raw score in <em>standard deviation</em> units. A <em>positive value</em> for a z-score indicates that the raw score is <em>above</em> the population mean, whereas a <em>negative value</em> tells us that the raw score is <em>below</em> the population mean. The formula to obtain this <em>z-score</em> is as follows:

\\ z = \frac{x - \mu}{\sigma} [1]

Where

\\ z is the <em>z-score</em>.

\\ \mu is the <em>population mean</em>.

\\ \sigma is the <em>population standard deviation</em>.

From the question, we have that:

  • Nelson's height is 68 in. In this case, the raw score is 68 in \\ x = 68 in.
  • \\ \mu = 70.7in.
  • \\ \sigma = 2.3in.

With all this information, we are ready to answer the next questions:

a. What is the positive difference between Nelson​'s height and the​ mean?

The positive difference between Nelson's height and the population mean is (taking the absolute value for this difference):

\\ \lvert 68-70.7 \rvert = \lvert 70.7-68 \rvert\;in = 2.7\;in.

That is, <em>the positive difference is 2.7 in</em>.

b. How many standard deviations is that​ [the difference found in part​ (a)]?

To find how many <em>standard deviations</em> is that, we need to divide that difference by the <em>population standard deviation</em>. That is:

\\ \frac{2.7\;in}{2.3\;in} \approx 1.1739 \approx 1.174

In words, the difference found in part (a) is 1.174 <em>standard deviations</em> from the mean. Notice that we are not taking into account here if the raw score, <em>x,</em> is <em>below</em> or <em>above</em> the mean.

c. Convert Nelson​'s height to a z score.

Using formula [1], we have

\\ z = \frac{x - \mu}{\sigma}

\\ z = \frac{68\;in - 70.7\;in}{2.3\;in}

\\ z = \frac{-2.7\;in}{2.3\;in}

\\ z = -1.1739 \approx -1.174

This z-score "tells us" that Nelson's height is <em>1.174 standard deviations</em> <em>below</em> the population mean (notice the negative symbol in the above result), i.e., Nelson's height is <em>below</em> the mean for heights in the club presidents of the past century 1.174 standard deviations units.

d. If we consider​ "usual" heights to be those that convert to z scores between minus2 and​ 2, is Nelson​'s height usual or​ unusual?

Carefully looking at Nelson's height, we notice that it is between those z-scores, because:

\\ -2 < z_{Nelson} < 2

\\ -2 < -1.174 < 2

Then, Nelson's height is <em>usual</em> according to that statement.  

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3 years ago
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