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yawa3891 [41]
4 years ago
6

Tim, Kara, and Ann Are working together to write a 4-page report. Each student is going to do an equal amount of writing. What f

raction of the entire report does each student need to write?
Mathematics
1 answer:
k0ka [10]4 years ago
5 0
1 1/3 of the entire report. If you split up the 4-page report by the number of people working on it, which is 3 you get the fraction 4/3 which you can change to a mixed number and get 1 1/3.
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While grading her students' most recent quiz on equation solving, Mrs. Jones calculated that approximately forty percent of her
EastWind [94]

The given equation is,

3(-n+4)+5n=2n

Part 1:

Solve the above equation for n.

Using distributive property of multiplication,

\begin{gathered} -3n+3\times4+5n=2n \\ -3n+12+5n=2n \end{gathered}

Now, group the like terms.

-3n+5n-2n+12=0

Now, add the like terms.

\begin{gathered} -5n+5n+12=0 \\ 0=-12 \end{gathered}

0=-12 is a false statement.

Since we obtained a false statement, the given equation has no solution.

So, option b is correct.

Part 2:

The option (a) is n=3.

If while solving an equation, a single value is obtained for the variable, then the equation has only a single solution. If n=3 is obtained after solving the equation, then the student should chose option (a) as the answer.

The option (b) is "no solution".

While solving an equation, if we obtain an equation which is mathematically false, then the equation will have no solution. So, no solution is chosen when no value is obtained for n and the final equation is mathematically false.

The option (c) is "infinitely many solutions".

While solving an equation, if we obtain an equation which is mathematically correct such as 0=0, 7=7 etc., then the equation will have infinietly many solutions. So, infinitely many solutions is chosen when no value is obtained for n and the final equation is mathematically correct.

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Answer:

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Step-by-step explanation:

This one is similar to the other one done with graphs , the only difference is we have equations instead of graphs.

Like the other one, we want to find f(2) and whatever that equals we plug into g(x) to find g(f(2))

So first lets find f(2)

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Step-by-step explanation:

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