All categories

3 years ago

A number is 42,300 when multiplied by 10 Find the product of this and 500?

Mathematics

2 answers:

Vaselesa [24]3 years ago

5 0

Answer: 2115000

I hope this helps and have a wonderful day filled with joy!

Simora [160]3 years ago

4 0

2115000

x*10= 42300

x= 4230

x*500

4230*500= 2115000

Hope this helps

You might be interested in

I need the answer to a parts I-iii and the answer to b

fomenos

Answer:

i) Mean = 72

ii) Median = 72

iii) Mode = 72

69, 70, 71, 72, 72, 72, 73, 74, 75

Step-by-step explanation:

a. To find mean, median and mode

It is given that all the 9 students get 72 marks.

Therefore the data set be,

72, 72, 72, 72, 72, 72, 72, 72 72

i) mean = (sum of data)/(total number of data)

= (9 * 72)/9 = 9

ii) Median - Central data in the data set when arranging ascending or descending order

72, 72, 72, 72, 72, 72, 72, 72 72

Median = 72

iii) Mode - Most repeating data in the data set

Here mode = 72

b). To find a data set

69, 70, 71, 72, 72, 72, 73, 74, 75

Here Mean, mode and median are all 72

3 0

4 years ago

There are 25 students in the school's Pep Club.

VashaNatasha [74]

Answer:

company b 10,080 dollars

Step-by-step explanation:

7 0

4 years ago

Which digit would make this number divisible by 6? 7 ___68 * A. 3 B. 4 C. 5 D. 8

Basile [38]

Answer:

Step-by-step explanation:

6 * 1228 = 7368

3 0

3 years ago

Someone also help me with this one

Gre4nikov [31]

I think it is because the down it is 8 m

so there is 6m it the top

so it should be

8-6=2

6 0

4 years ago

PLS HELP ME WITH THIS!!!!!! HOW DID THEY GET 80ft^2

noname [10]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Determine the surface area of the right square pyramid.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

The formula for finding the surface area of a right square pyramid is ⇨ b² + 2bl, where

b = base of the right square pyramid
l = slant height of the right square pyramid.

In the given figure,

base (b) = 4 ft.
slant height (l) = 8 ft.

Now, let's substitute the values of b & l in the formula & solve it :-

$\sf \: {b}^{2} + 2bl \\ = \sf \: {4}^{2} + 2 \times 4 \times 8 \\ = \sf \: 16 + 8 \times 8 \\ = \sf \: 16 + 64 \\ = \huge\boxed{\boxed{ \bf 80 \: ft ^{2} }}$

So, the surface area of the right square pyramid is 80 ft².

7 0

3 years ago