4. What do your measurements in #3 tell you about the lengths of PR and QS ? Explain your thinking and then

Which question is biased?

pishuonlain [190]

I think the answer is B. because it says "waste of time"

4 0

3 years ago

Read 2 more answers

Suppose you own a car that gets 35 miles per

SSSSS [86.1K]

Answer:

$30

Step-by-step explanation:

840/35 = 24 gallons

24*1.25 = 30 dollars

7 0

1 year ago

The feet of the average adult woman are 24.6 cm long, and foot lengths are normally distributed. If 16% of adult women have feet

nevsk [136]

Answer:

Approximately 16% of adult women have feet longer than 27.2 cm.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The feet of the average adult woman are 24.6 cm long

This means that $\mu = 24.6$

16% of adult women have feet that are shorter than 22 cm

This means that when $X = 22$ , Z has a p-value of 0.16, so when $X = 22, Z = -1$ . We use this to find $\sigma$

$Z = \frac{X - \mu}{\sigma}$

$-1 = \frac{22 - 24.6}{\sigma}$

$-\sigma = -2.6$

$\sigma = 2.6$

Approximately what percent of adult women have feet longer than 27.2 cm?

The proportion is 1 subtracted by the p-value of Z when X = 27.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{27.2 - 24.6}{2.6}$

$Z = 1$

$Z = 1$ has a p-value of 0.84.

1 - 0.84 = 0.16

0.16*100% = 16%.

Approximately 16% of adult women have feet longer than 27.2 cm.

3 0

3 years ago

Find the complete factorization of the expression. 48x + 56xy

meriva

<span>8x(6 + 7y) this is your answer hope it works!</span>

7 0

3 years ago

A 20.3 kg person climbs up a uniform ladder with negligible mass. The upper end of the ladder rests on a frictionless wall. The

VMariaS [17]

Answer:

Q = arctan(7.1739) = 82.06

Step-by-step explanation:

Given:

- The mass of the person m = 20.3 kg

- The distance traveled up the ladder s = 1.1 m

- The gravitational constant g = 9.8 m/s^2

- The coefficient of static friction u_s = 0.23

- Total length of the ladder

Find:

The minimum angle θ, that would allow the person to climb without ladder slipping

Solution:

- Taking moments about point of ladder and wall contact A to be zero:

-F_n,b*cos(Q)*4 - F_f*sin(Q)*4+ m*g*cos(Q)*2.6 = 0

- Taking Sum of vertical forces to be zero:

F_n,b - m*g = 0

F_n,b = m*g

- The frictional force F_f is given by:

F_f = u_s*F_n,b = u_s*m*g

- Plug the values back in:

- m*g*cos(Q)*4 + u_s*m*g*sin(Q)*4 - m*g*cos(Q)*2.6 = 0

Simplify:

4*cos(Q) + 2.6*cos(Q) = u_s*4*sin(Q)

6.6*cos(Q) = 4*u_s*sin(Q)

tan(Q) = 6.6 / 4*u_s

- Plug in the values:

tan(Q) = 6.6 / 4*0.23

Q = arctan(7.1739) = 82.06

4 0

3 years ago