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Neko [114]
3 years ago
7

Graph f(x)=12x+2. Use the line tool and select two points to graph the line.

Mathematics
1 answer:
Alex73 [517]3 years ago
3 0

Answer:

(0,2) and (1,14)

Graph is attached.

Step-by-step explanation:

Let us find  y intercept

When x=0, y  = f(x) =2

Hence one point is (0,2)

Other point is let x = 1,

y =12(1)+2 =14

(1,14) (0,2) are plotted and joined.

Graph is attached.

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xz_007 [3.2K]
The answer is 1.4 x 10^3 Or 1400
Rewrite the equation as
(2x7) x (10^6 x 10^4) then calculate from there to get your answer
4 0
3 years ago
Co-payment is 20% of $23,890 , her co-payment is
Sidana [21]

the answer to the question is 4,778

3 0
3 years ago
30 2/9x3= 50 5/8 plz, plz, Thanks
9966 [12]

Answer:

141.291667 or about 141

Step-by-step explanation:

4 0
3 years ago
Americans receive an average of 20 Christmas cards each year. Suppose the number of Christmas cards is normally distributed with
soldier1979 [14.2K]

The distribution of X is X ~ N (20 , 6) and the probability that this American will receive no more than 24 Christmas cards this year is 0.7486.

<h3>Probability</h3>

a. Distribution

X ~ N (20 , 6)

b. P(x ≤24)

= P[(x - μ ) / σ  (24 - 20) / 6]

= P(z  ≤0.67)

=  0.74857

=0.7486

Hence:

Probability = 0.7486

c. P(21 < x < 26)

= P[(21 - 26)/ 6) < (x - μ  ) / σ   < (24 - 20) / 6) ]

= P(-0.83 < z < 0.67)

= P(z < 0.67) - P(z < -0.)

=  0.74857- 0.2033

= 0.54527

Hence:

Probability =0.54527

d. Using standard normal table ,

P(Z < z) = 66%

P(Z < 0.50) = 0.66

z = 0.50

Using z-score formula,

x = z×  σ +  μ

x = 0.50 × 6 + 20 = 23

23 Christmas cards

Therefore the distribution of X is X ~ N (20 , 6) and the probability that this American will receive no more than 24 Christmas cards this year is 0.7486.

Learn more about probability here:brainly.com/question/24756209

#SPJ1

8 0
2 years ago
GCF of 35,5,70 is???
Vanyuwa [196]

Answer:

5

Because, five can go into 5, 35 and 70. Nothing else bigger can. If we went bigger we would be going over five.

Hope this helps :)

6 0
3 years ago
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