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Setler [38]
3 years ago
12

The data in which table represents a linear function that has a slope of zero? A 2-column table with 5 rows. Column 1 is labeled

x with entries negative 5, negative 4, negative 3, negative 2, negative 1. Column 2 is labeled y with entries 5, 5, 5, 5, 5. A 2-column table with 5 rows. Column 1 is labeled x with entries 1, 2, 3, 4, 5. Column 2 is labeled y with entries negative 5, negative 4, negative 3, negative 2, negative 1. A 2-column table with 5 rows. Column 1 is labeled x with entries negative 5, negative 4, negative 3, negative 2, negative 1. Column 2 is labeled y with entries 5, 4, 3, 2, 1. A 2-column table with 5 rows. Column 1 is labeled x with entries 5, 5, 5, 5, 5. Column 2 is labeled y with entries negative 5, negative 4, negative 3, negative 2, negative 1.
Mathematics
2 answers:
jeyben [28]3 years ago
7 0

Answer:

A is the answer

Step-by-step explanation:

just took the test

kondaur [170]3 years ago
6 0

Answer:

A 2-column table with 5 rows. Column 1 is labeled x with entries negative 5, negative 4, negative 3, negative 2, negative 1. Column 2 is labeled y with entries 5, 5, 5, 5, 5.

Step-by-step explanation:

The table with all y-values the same will graph as a horizontal line, a line with a slope of zero.

Apparently, the first table is like that.

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Answer:

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Step-by-step explanation:

General Equation of circle is

(x-x_1)^{2} +(y-y_1)^{2} = r^{2}----------- (1)

Here

(x_1, y_1)= (0, 0)

Radius r is distance from origin (x1, y1) to point (x2, y2)=(-3, -6)

r=\sqrt{(x_2-x_1)^{2} + (y_2-y_1)^{2} }

r= \sqrt{(-3-0)^{2} + (-6-0)^{2} }

r= \sqrt{9+36}

r=\sqrt{45}

Substituting values in equation (1)

(x-0)^{2} +(y-0)^{2} =( \sqrt{45})^{2}

x^{2} +y^{2} = 45

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