The sign should be flipped to show that the hours of community service are greater than, or equal to 10 hours.
Answer:
the object is in the air on the time interval (0.24 sec, 6.51 sec)
Step-by-step explanation:
The object is 'in the air' for all t such that h> 0. We need to find the roots of h = -16t^2 + 108t - 25 = 0. From the graph we see that both t values are positive. Once we find them, we subtract the smaller t from the larger t, which results in the length of time the object is in the air.
Use the quadratic formula to find the roots of h(t). The coefficients of t are {-16, 108, -25}, and so the discriminant b^2 - 4ac is
108² - 4(-16)(-25) = 11664 - 1600 = 10064, whose square root is 100.32.
Then the quadratic formula x = (-b ± √[b² - 4ac)/(2a) becomes
-108 ± 100.32 108 ± 100.32
t = ---------------------- = --------------------- = 3.375 ± 3.135
2(-16) 32
or t = 6.51 or t = 0.24 (both times expressed in seconds).
So, again, the object is in the air on the time interval (0.24 sec, 6.51 sec)
Answer:
x =−1−√93/23,−1+√93/23
Step-by-step explanation:
x=0.37581090…,−0.46276742...
Answer:
Rate of change in elevation = 0.6 in/year
Step-by-step explanation:
Note:
Current elevation (Missing) = 7,602 feet
Given:
Old elevation = 7,602 feet
Number of year = 7,600
Find:
Rate of change in elevation
Computation:
Change in elevation = 7,602 - 7,600
Change in elevation = 2 ft
Change in elevation = 2 x 12 = 24 inches
Rate of change in elevation = 24 / 40
Rate of change in elevation = 0.6 in/year
Answer:
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Step-by-step explanation:
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