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Volgvan
2 years ago
10

ABC below is a right triangle where the measure of AB is 6 units and the measure of ∠A is 50°. What would the area of the triang

le be?
A. 18sin50°
B. 18tan50°
C. 6sin50°
D. 36sin50°

Mathematics
2 answers:
Taya2010 [7]2 years ago
8 0
B. is the thing dear friend
ira [324]2 years ago
5 0

Answer:

18 tan 50

Option B

Step-by-step explanation:

Given is a picture of triangle ABC.

The triangle is right angled at B.

AB =6 and angle A = 50

Using trig ratios we have

\frac{AB}{AC} =\frac{6}{y} =cos50 where y is length of hypotenuse = AC

Solving y = 6sec 50

Area of triangle = \frac{1}{2} (AB)(AC) sin 50

=\frac{1}{2} (6)(6sec50)(sin50)\\= 18 tan 50

You might be interested in
In △ABC, m∠A=19°, a=13, and b=14. Find c to the nearest tenth.
34kurt
We know that
Applying the law of sines

step 1
Find the value of angle B
a=13
b=14
A=19°
so

 \frac{a}{sin A} = \frac{b}{sin B} \\ a*sin B=b*sin A \\ sin B= \frac{b}{a}*sin A \\ sin B= \frac{14}{13} *sin 19 \\ sin B=0.3506 \\ B=arc sin(0.3506) \\ B=20.5°

step 2
with angle A and angle B find the angle C
A+B+C=180-----> solve for C
C=180-(A+B)------> C=180-(19+20.5)-----> C=140.5°

step 3
\frac{a}{sin A} = \frac{c}{sin C} \\ a*sin C=c*sin A \\ c=a* \frac{sin C}{sin A}  \\ c=13* \frac{sin 140.5}{sin 19}  \\ c=25.4

the answer is
the value of c is 25.4



3 0
3 years ago
Help Plss simply can u show step by step ?-4(8x-4)+3x
Vikentia [17]

Answer:

-4(8x-4)+3x = -29x+16

Step-by-step explanation:

1. Simplify -4(8x-4) by using the distribution property:

<u>-4(8x) = -32x and -4(-4) = 16 so -4(8x-4) = -32x+16</u>

2. Add 3x to the remaining equation:

<u>-32x+16+3x = -29x+16 </u>

3. The answer is:

<u> -29x+16 </u>

6 0
3 years ago
Verify which of the following are identities.
-Dominant- [34]

Answer:

Only the second equation is an identity

Step-by-step explanation:

$8 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=8 \csc(\theta)$

<u>Note that </u>

\tan^2(\theta)\csc^2(\theta)=\sec^2(\theta)

<u>You can confirm it: </u>

$\frac{\sin^2(\theta)}{\cos^2(\theta)}\cdot    \frac{1}{\sin^2(\theta)}= \frac{1}{cos^2(\theta)}= \sec^2(\theta)$

<u>Therefore</u>

$8 \frac{\sec^2(\theta)}{\sec(\theta)} =8 \csc(\theta)$

$8 \frac{\sec(\theta)}{1} =8 \csc(\theta)$

8\sec(\theta)=8\csc(\theta)

<h2>It is not an Identity</h2>

<u>Let's the second one</u>

$13 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=13\sec(\theta)$

In this case, we already performed the calculations, so it is true. It is an Identity.

3 0
2 years ago
The end points of Line GH are G (10,2) and H(4,8). Find the coordinates of the midpoint M.
nikitadnepr [17]

Answer:

(10-4)/2 , (2-8)/2

6/2 , -6/2

Midpoint = (3,-3)

7 0
2 years ago
Please tell me what x is 3(x+6)=48
Alekssandra [29.7K]

Answer

X=10

Step by step explanation

48÷3 = 16

16-6 = 10

7 0
3 years ago
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