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Volgvan
3 years ago
10

ABC below is a right triangle where the measure of AB is 6 units and the measure of ∠A is 50°. What would the area of the triang

le be?
A. 18sin50°
B. 18tan50°
C. 6sin50°
D. 36sin50°

Mathematics
2 answers:
Taya2010 [7]3 years ago
8 0
B. is the thing dear friend
ira [324]3 years ago
5 0

Answer:

18 tan 50

Option B

Step-by-step explanation:

Given is a picture of triangle ABC.

The triangle is right angled at B.

AB =6 and angle A = 50

Using trig ratios we have

\frac{AB}{AC} =\frac{6}{y} =cos50 where y is length of hypotenuse = AC

Solving y = 6sec 50

Area of triangle = \frac{1}{2} (AB)(AC) sin 50

=\frac{1}{2} (6)(6sec50)(sin50)\\= 18 tan 50

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3 years ago
Given: △KLM, LM=20 3 <br> m∠K=105°, m∠M=30°<br> Find: KL and KM
hjlf

Okay, so the angle of K is 45° (180 - 135).

Draw a line that goes straight down from angle L and let's say that point is point Z. You can see that this triangle can be separated into two special triangles: the 45 45 90 triangle on the left (ΔLKZ) and the 30 60 90 triangle (ΔLMZ) on the right.

I don't know if you've learned this yet (just google them if you're confused):                                                                       - for a 45 45 90 triangle the sides are x, x, and x√2.                                                 - for a 30 60 90 triangle the sides are x, 2x, and x√3.

Since we know that LM is 20√3, using the 30 60 90 trick, you can see that LZ is 10√3 and MZ is 30.

Next, since LZ is 10 sqrt(3), using the 45 45 90 trick, <em>KL is 10√6</em> and KZ is 10 sqrt(3). Therefore, KM = KZ + MZ = <em>10√3 + 30</em>

<u>The answer: KL is 10√6, KM is 10√3 + 30</u>

(I'm sorry it's such a long explanation, pictures would have been better)

6 0
3 years ago
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