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2 years ago

Simplyify (-7)^0 PLEASE HELPP

Mathematics

2 answers:

r-ruslan [8.4K]2 years ago

5 0

$a^0=1$ for all $a\in\mathbb{R}$

$(-7)^0=1$

BartSMP [9]2 years ago

3 0

Answer:

Step-by-step explanation:

anything to the power of 0 is 1

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Bonus: Mr. Rao is planning on making a shed in his backyard (see his plan in the image below). However, local laws require sheds

Leviafan [203]

Answer:

North 10 feet, and East 5 feet.

Step-by-step explanation:

So we know that North is ^ way. We also know that East is > way.

These are the two directions we must go, since the property line is both South and West of the shed.

The shed is 10ft East of the property line, and we must be 15ft in that direction. So we must go another 5ft East.

Now, the shed is 5ft North of the property line, and we must be 15ft in that direction. So we must go another 10 feet North.

Hope this helps!

6 0

2 years ago

Aaron was offered a job that paid a salary of \$57,000$57,000 in its first year. The salary was set to increase by 1% per year e

Jobisdone [24]

Answer:

The total amount received is: $1906650

Step-by-step explanation:

Given

$a = \$57000$ --- initial

$b = 1\%$ --- rate

$n = 29$ --- time

Required

Determine the total amount at the end of 29 years

The given question is an illustration of geometric progression, and we are to solve for the sum of the first n terms

Where $n = 29$

$r = 1 + b$

$r = 1 + 1\%$

Express percentage as decimal

$r = 1 + 0.01$

$r = 1.01$

The required is the calculated using:

$S_n = \frac{a(r^n - 1)}{r - 1}$

So, we have:

$S_n = \frac{57000 * (1.01^{29} - 1)}{1.01 - 1}$

$S_n = \frac{57000 * (1.3345- 1)}{0.01}$

$S_n = \frac{57000 * 0.3345}{0.01}$

$S_n = \frac{19066.5}{0.01}$

$S_n = 1906650$

<em>The total amount received is: $1906650</em>

8 0

2 years ago

Please help me on this it’s due please help me

GuDViN [60]

9 1/2 * 15.15 = $143.925 dollar

3 0

2 years ago

Is math hard or easy!<br> comment down below

levacccp [35]

HARD!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

3 0

2 years ago

Read 2 more answers

A university researcher wants to estimate the mean number of novels that seniors read during their time in college. An exit surv

lys-0071 [83]

Answer:

Population mean = 7 ± 2.306 × $\frac{2.29}{\sqrt{9} }$

Step-by-step explanation:

Given - A university researcher wants to estimate the mean number

of novels that seniors read during their time in college. An exit

survey was conducted with a random sample of 9 seniors. The

sample mean was 7 novels with standard deviation 2.29 novels.

To find - Assuming that all conditions for conducting inference have

been met, which of the following is a 94.645% confidence

interval for the population mean number of novels read by

all seniors?

Proof -

Given that,

Mean ,x⁻ = 7

Standard deviation, s = 2.29

Size, n = 9

Now,

Degrees of freedom = df

= n - 1

= 9 - 1

= 8

⇒Degrees of freedom = 8

Now,

At 94.645% confidence level

α = 1 - 94.645%

=1 - 0.94645

=0.05355 ≈ 0.05

⇒α = 0.5

Now,

$\frac{\alpha}{2} = \frac{0.05}{2}$

= 0.025

Then,

$t_{\frac{\alpha}{2}, df }$ = 2.306

∴ we get

Population mean = x⁻ ± $t_{\frac{\alpha}{2}, df }$ × $\frac{s}{\sqrt{n} }$

= 7 ± 2.306 × $\frac{2.29}{\sqrt{9} }$

⇒Population mean = 7 ± 2.306 × $\frac{2.29}{\sqrt{9} }$

3 0

3 years ago

Read 2 more answers