PLEASE HELP ME IM BEGGING U .

Find the missing term in the geometric sequence. 1, 17, 289,

Greeley [361]

4,913 is the correct answer.
Please vote my answer brainliest! Thanks.

6 0

3 years ago

Laurie buys four bags of candy with 10 pieces of candy in each bag. Her father then gives her 5 more pieces of candy. Laurie wan

lina2011 [118]

Answer:

3 pieces left over

Step-by-step explanation:

Laurie has a total of 45 pieces of candy, if she has 6 friends, you can do

$45 \div 6 = 7.5$

each friend can get 7 pieces of candy

$7 \times 6 = 42$

if each friend gets 7 pieces, you have used 42 pieces out of you total 45

$45 - 42 = 3$

which leaves 3 pieces left over.

3 0

3 years ago

If r and s are positive integers, is \small \frac{r}{s} an integer? (1) Every factor of s is also a factor of r. (2) Every prime

Yuri [45]

Answer:

If statement(1) holds true, it is correct that $\small \frac{r}{s}$ is an integer.

If statement(2) holds true, it is not necessarily correct that $\small \frac{r}{s}$ is an integer.

Step-by-step explanation:

Given two positive integers $r$ and $s$ .

To check whether $\small \frac{r}{s}$ is an integer:

Condition (1):

Every factor of $s$ is also a factor of $r$ .

$r \geq s$

Let us consider an example:

$s = 5^2 \cdot 2\\r = 5^3 \cdot 2^2$

$\dfrac{r}{s} = \dfrac{5^3\cdot2^2}{5^2\cdot2} = 10$

which is an integer.

Actually, in this situation $s$ is a factor of $r$ .

Condition 2:

Every prime factor of s is also a prime factor of r.

(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)

Let

$r = 2^2\cdot 5\\s =2^4\cdot 5$

$\dfrac{r}{s} = \dfrac{2^3\cdot5}{2^4\cdot5} = \dfrac{1}{2}$

which is not an integer.

So, the answer is:

If statement(1) holds true, it is correct that $\small \frac{r}{s}$ is an integer.

If statement(2) holds true, it is not necessarily correct that $\small \frac{r}{s}$ is an integer.

8 0

3 years ago

On Claudia's birthday, her parents open a savings account and deposit SS. They also deposit $50 each

Pie

Wacom down straight to logo and and make sure he don’t get up

3 0

3 years ago

Can someone explain to me in words how to do this problem 3x+122=22x-11

inn [45]

When you have this type of problem, you need to combine the like-terms and isolate the variable.

3x + 122 = 22x - 11

Add 11 to both sides to get rid of it

3x + 122 + 11 = 22x - 11 + 11 (-11 + 11=0)

3x + 133 = 22x

Then you would bring the 3x to the other side, so subtract 3x from both sides

3x + 133 = 22x

-3x -3x

133 = 22x - 3x

133 = 19x

Then divide both sides by 19 to isolate x

133/19 = 19x/19

133/19 = 7, so x = 7

Hope this helps!!

8 0

3 years ago