The inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
<h3>How to determine the inverse relation?</h3>
The function is given as
f(x)=1/3x^2-3x+5
Start by rewriting the function in vertex form
f(x) = 1/3(x - 9/2)^2 -7/4
Rewrite the function as
y = 1/3(x - 9/2)^2 -7/4
Swap x and y
x = 1/3(y - 9/2)^2 -7/4
Add 7/4 to both sides
x + 7/4= 1/3(y - 9/2)^2
Multiply by 3
3x + 21/4= (y - 9/2)^2
Take the square roots
y - 9/2 = √(3x + 21/4)
This gives
y = 9/2 + √(3x + 21/4)
Hence, the inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
Read more about inverse functions at:
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She has 1/2 cup left. 3/4 + 3/8 equals 1 1/8 subtract that by 5/8 and you have 1/2
<em>Answer:</em>
<em>2</em>
<em>Step-by-step explanation:</em>
<em>The factors of 72: 1, </em><em>2</em><em>, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72</em>
<em>The factors of 98: 1, </em><em>2</em><em>, 7, 14, 49, 98
</em>
<em>Your greatest common factor is 2.</em>
<em>Hope this helps. Have a nice day.</em>
Answer:
Step-by-step explanation:
24)
200= 3(21) + 4x
200= 63 +4x
-63 -63
137= 4x
divide each side by 4
34 = x
c
25)
.5(pi)= about 1.6
1.6(2.5)= 4
c
44)
equation- T= 12.17+0.75v
105.75= 12.17 + .75v
-12.17 -12.17
93.58= .75v
divide each side by .75
answer 125
