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valkas [14]
3 years ago
7

If a=2i-3j-k and b=i+4j+2k what us ab​

Mathematics
1 answer:
Masteriza [31]3 years ago
8 0

Answer:

2i²+5ij+3ik-12j²-10jk-2k²

Step-by-step explanation:

a=2i-3j-k

b=i+4j+2k

ab = (2i-3j-k) (i+4j+2k)

Multiply both bracket by expanding the bracket

2i(i+4j+2k)-3j(i+4j+2k)-k(i+4j+2k)

Multiply

2i²+8ij+4ik-3ij-12j²-6jk-ik-4jk-2k²

Collect like terms

2i²+8ij-3ij+4ik-ik-12j²-6jk-4jk-2k²

2i²+5ij+3ik-12j²-10jk-2k²

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(x²+10x+7)(2x-1) = 2x³+19x²+4x-7 show the steps
sasho [114]
Answer: See below

Explanation:
(x^2+10x+7)(2x-1) = 2x^3+19x^2+4x-7
2x^3-x^2+20x^2-10x+14x-7 = 2x^3+19x^2+4x-7

2x^3+19x^2+4x-7 = 2x^3+19x^2+4x-7

6 0
3 years ago
A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.00 m/s. The car is a distan
enyata [817]
S=\frac{d}{t},\ where\ s-speed,\ d-distance,\ t-time\\t=\frac{d}{S}\\\\d+37.2-bear\ distance\\\\Time\ (tourist\ tourist\ and\ bear)\ will\ be\ the\ same\ so\ we\\ should\ comparise\ them:\\\\\frac{d}{4}=\frac{d+37.2}{4.96}\\\\4.96d=4(d+37.2)\\\\4.96d=4d+148.8\\\\4.96d-4d=148.8\\\\0.96d=148.8\\\\d=155m\\\\Maximum\ value\ of\ d\ is\ 155m
3 0
3 years ago
The function h(t)=−16t(t−7) models the height of an object at any time t after it is launched, where t is measured in seconds. A
Kipish [7]

Answer:

2.65secs

Step-by-step explanation:

Give:

The function h(t)=−16t(t−7) models

the object will hit the ground at h= 0

h(t)=−16t(t−7)

0= -16t(t−7)

0= -16t^2 + 112

16t^2 = 112

t^2 = 7

t= √7

t=2.65secs

Hence, the object object hit the ground at 2.65secs

7 0
3 years ago
How do you find a reasonable domain and range for number 13?
kogti [31]
They have 3 packages so p=3
so N(p) = 90p 
therefore N(3) = 270
they cannot feed more than 270 people so the range must be N(p)>270
7 0
3 years ago
8
yanalaym [24]
ITS Y,X I just took it. I hope this helped you
8 0
3 years ago
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