The function h(t)=−16t(t−7) models the height of an object at any time t after it is launched, where t is measured in seconds. A

Question

3 years ago

11

fter how many seconds will the object hit the ground?

1 answer:

Kipish [7] · Answer 1 · 2022-04-25T14:15:40+03:00

Kipish [7]3 years ago

7 0

Answer:

2.65secs

Step-by-step explanation:

Give:

The function h(t)=−16t(t−7) models

the object will hit the ground at h= 0

h(t)=−16t(t−7)

0= -16t(t−7)

0= -16t^2 + 112

16t^2 = 112

t^2 = 7

t= √7

t=2.65secs

Hence, the object object hit the ground at 2.65secs