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kondaur [170]
3 years ago
9

The value of 3 in 6300 is

Mathematics
2 answers:
Alex777 [14]3 years ago
5 0
300
Because its in the one hundred column
Rainbow [258]3 years ago
4 0
The value of 3 in 6300 is in the hundreds column.
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SOLVE FOR X 3x +5 = x -10 A. -5/4 B. -5 C. -15/2 D. -15 OA B. D​
kifflom [539]

Hello!

\large\boxed{\text{C.} \frac{-15}{2}}

3x + 5 = x - 10

Solve for x by isolating the variable.

Subtract 5 from both sides:

3x + 5 - 5 = x - 10 - 5

3x = x - 15

Subtract x from both sides:

3x - x = x - x - 15

2x = -15

Divide both sides by 2:

2x /2 = -15 / 2

x = -15/2.

4 0
3 years ago
Read 2 more answers
Line AB contains points A (-3,5) and B (-3,3). Line AB has a slope that is
posledela

Answer:

The slope of line AB is ( 3 - 5 ) / ( - 3 + 3 ) = ( - 2 ) / 0 = - ∞;

Therefore, Line AB has slope that is undefined.

Step-by-step explanation:

6 0
4 years ago
Let f(x) = 9x3+ 21x2^ - 14 and g(x) = 3x + 1. Find "<br>f (x) over g (x)​
kondor19780726 [428]

Answer:

\frac{f(x)}{g(x)}=3x^2+6x-2-\frac{12}{3x+1}

Step-by-step explanation:

The first function is f(x)=9x^3+21x^2-14

The second function is g(x)=3x+1.

\frac{f(x)}{g(x)}=\frac{9x^3+21x^2-14}{3x+1}

We perform the long division as shown in the attachment to obtain the quotient as: Q(x)=3x^2+6x-2 and remainder R=-12.

Therefore:

\frac{f(x)}{g(x)}=3x^2+6x-2-\frac{12}{3x+1}

where x\ne -\frac{1}{3}

7 0
4 years ago
The figure below shows part of a stained-glass window depicting the rising sun. Which function can be used to find the area of t
Kryger [21]

Answer:

A(w) = w^2 + 5w - \frac{1}{8}\pi w^2

Step-by-step explanation:

A = the area of the region outside the semicircle but inside the rectangle

w = the width of the rectangle or diameter of the semicircle

Since "A" is determined by "w", therefore, "A" is a function of "w" = A(w).

A(w) = (area of rectangle) - (area of semicircle)

A(w) = (l*w) - (\frac{1}{2} \pi r^2)

Where,

lenght of rectangle (l) = w + 5

width of rectangle (w) = w

r = ½*w = \frac{w}{2}

Plug in the values:

A(w) = ((w + 5)*w) - (\frac{1}{2} \pi (\frac{w}{2})^2)

A(w) = ((w + 5)*w) - (\frac{1}{2} \pi (\frac{w}{2})^2)

Simplify

A(w) = (w^2 + 5w) - (\frac{1}{2} \pi (\frac{w^2}{4})

A(w) = w^2 + 5w - \frac{1}{2}*\pi*\frac{w^2}{4}* \pi

A(w) = w^2 + 5w - \frac{1*\pi*w^2}{2*4}

A(w) = w^2 + 5w - \frac{1*\pi w^2}{8}

A(w) = w^2 + 5w - \frac{1}{8}\pi w^2

3 0
3 years ago
Zena needs a salesperson. Salesperson A is offering his services for an initial $100 in addition to $5 per hour. Salesperson B i
77julia77 [94]

Answer:

Step-by-step explanation:

The correct question is

Zena needs a salesperson. Salesperson A is offering his services for an initial $50 in addition to $5 per hour. salesperson B is offering her services for an initial $40 in addition to $7 per hour. When will the two coaches charge the same amount of money?

Let

x ----> the number of hours

y ----> the total charge

we know that

Salesperson A

------> equation A

Salesperson B

------> equation B

To find out when the two coaches charge the same amount of money, equate equation A and equation B and solve for x

7x+40=5x+50

7x-5x=50-40

2x=10

<h2>x=5 hours i think just im not sure but i tried</h2>
7 0
3 years ago
Read 2 more answers
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