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Mariana [72]
3 years ago
11

Find the value of x that makes m || n x=

Mathematics
1 answer:
kogti [31]3 years ago
4 0
180-73
=107
X would equal 107
You might be interested in
Guys please help me !!!!
mario62 [17]

mode = 43

the mode is the value which occurs most

43  occurs 3 times, 38 twice and the others only once

Hence 43 is the mode


6 0
4 years ago
How do you do this using a graphing calculator?
lesya [120]
Press the button COS( )
Type in the number, close the parentheses
Press Enter (MAKE SURE CALC IN DEGREE MODE)
4 0
4 years ago
A triangle height is 2/4 mm and the base is 8 mm. What is the area of the triangle?
Darina [25.2K]

Answer:

the answer would be 2mm^2

8 0
3 years ago
Read 2 more answers
Given A-<br> 2 2<br> 1 3<br> what is A-¹?
devlian [24]

The inverse of matrix A = \left[\begin{array}{cc}2&2&1&3\\\end{array}\right] is A^{-1} = \frac{1}{4} \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|      

The given matrix is A = \left[\begin{array}{cc}2&2&1&3\\\end{array}\right]

The inverse of a matrix is given by

A^{-1} = \frac{1}{|A|} adjA                   ...(1)

Now, determinant of matrix A is

|A| = \left|\begin{array}{cc}2&2&1&3\\\end{array}\right|

= (3)(2) - (2)(1)

= 6 - 2

= 4

Now, adjoint A will be

A_{11} = 3

A_{12} = -1

A_{21} = -2

A_{22} = 2

AdjA = \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|

Now, substituting the values of |A| and AdjA in equation (1), we get

A^{-1} = \frac{1}{4} \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|        

Therefore, A^{-1} = \frac{1}{4} \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|      

Know more about Inverse of Matrix: -brainly.com/question/12442362

#SPJ9

     

7 0
2 years ago
Please someone help me !! :(
geniusboy [140]

Answer: 27 times bigger.

Step-by-step explanation:

You need to use the following formula to find the volume of a Square pyramid:

V=\frac{1}{3}s^2h

Where "s" is the edge of a side of the square base and "h" is the height of the pyramid.

Knowing that:

s_A=12\ in\\\\h_A=8\ in\\\\\\s_B=36\ in\\\\h_B=24\ in

You can find the volume of the Pyramid A and the volume of the Pyramid B:

V_A=\frac{1}{3}(12\ in)^2(8\ in)\\\\V_A=384\ in^3\\\\\\V_B=\frac{1}{3}(36\ in)^2(24\ in)\\\\V_B=10,368\ in^3

Finally divide the volume of the Pyramid B and the volume of the Pyramid A, in order to find how many times bigger than the Pyramid A is the Pyramid B.

You get:

\frac{10,368\ in^3}{384\ in^3}=27

7 0
4 years ago
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