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german
3 years ago
14

Please help with math question below

Mathematics
2 answers:
Umnica [9.8K]3 years ago
5 0
Edges that are perpendicular to PR basically means what edges make a 90° angle with PR.

Those edges are HP , RA, TR and QP.

Hence, the answer is A, B and C.
mixer [17]3 years ago
3 0
I am pretty sure its qt 
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What is the solution to the system of equations?
Karolina [17]

Answer: (1,3) or x = 1 and y = 3

Step-by-step explanation:

The solution is the intersection thus the answer is (1,3) or x = 1 and y = 3

4 0
2 years ago
Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based
Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for \mathrm{sinc}\,x about x=0:

\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}

Then the Taylor series for

f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt

is obtained by integrating the series above:

f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}

We have f(0)=0, so C=0 and so

f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}

which converges by the ratio test if the following limit is less than 1:

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}

Like in the linked problem, the limit is 0 so the series for f(x) converges everywhere.

7 0
3 years ago
What is the domain of the function shown
Sedaia [141]
It would be choice b.
The domain is the range of x values which in this case is from -5 to 3.
4 0
3 years ago
Read 2 more answers
Here is a growing pattern of squares:
Flura [38]

Answer:

squares in Step n. f (n) = 8 + 3(n – 1} for n > 1 /(1) = 8, /{n2) = 3+f (n – 1) for n > 2 01)= 8, 7 (n) = 8= ƒ(n=1) forn> 2 Df1)= 3 -8 (n- 1) forn > 1 Of (n) - 37 + 5 for n > 1 32+5 for n>1 CS (n) 3+ an forn 1

Step-by-step explanation:

3 0
2 years ago
Find an equation of the line passing through the point (2, -3) and has slope -4. Then rewrite your linear equation in the slope-
Tresset [83]

Answer:

y=-4x+5

Step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

-3. -3

y=-4x+5

8 0
3 years ago
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