Where do lines modeled by equations y=-7/8x+1/4 and y=-3/4x+1/2 intersect

2 answers:

5 0

If they intersect they have the same x and y values so we can say y=y which can be expressed as:

-7x/8+1/4=-3x/4+1/2 make all terms have a common denominator of 8

-7x/8+2/8=-6x/8+4/8 now multiply all terms by 8

-7x+2=-6x+4 add 6x to both sides

-x+2=4 subtract 2 from both sides

-x=2 divide both sides by -1

x=-2, now we solve for y using either original equation...

y=-3(-2)/4+1/2

y=6/4+1/2

y=6/4+2/4

y=8/4

y=2 so the lines intersect at the point:

(-2, 2)

iris [78.8K]3 years ago

5 0

The lines would intersect at (-2,2)

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PLSS HLP ME. Im so sry i am just rlly rlly not smart

podryga [215]

Answer:

3/4w + 2b

Step-by-step explanation:

Just pretty much go through the whole thing and evaluate it word for word.

So 3/4 of w is essentially 3/4w

Add a plus (+) sign to signify addition

The product of 2 and b can be written as 2b or as 2×b, your preference

7 0

2 years ago

A circle has its center at the center of a square with 26-inch sides. Using 3.14 for pi, find the area of the square not covered

AlladinOne [14]

For squrae
area=side²
perimiter=4(side)

for circle
area=pir²
circumference=2pir

side=diameter, diameter/2=radius=side/2

find area not covered
that is areasquare-areacircle
areasquare=26²=676 sqauare inches
areaciecle, diameter=side, 26/2=13, area=pi13²=169*3.14=530.66 square inches

areanotcovered=676-530.66=145.34 square inches not coverd

ratio of perimiter to circumferece
perimiter=4*26=104
circumference=2pir=2pi13=26pi=26*3.14=81.64
circumference to perimiter is 81.64/104=0.785

7 0

3 years ago

Read 2 more answers

Can someone help with this

grigory [225]

Answer:

∠4 = 50°

Step-by-step explanation:

∠1 + ∠5 = 100°, but ∠1 = ∠5 ( corresponding angles ), hence

∠1 = ∠5 = 50°

∠4 = ∠1 = 50° ( vertical angles )

4 0