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frez [133]
3 years ago
6

Where do lines modeled by equations y=-7/8x+1/4 and y=-3/4x+1/2 intersect

Mathematics
2 answers:
vlabodo [156]3 years ago
5 0
If they intersect they have the same x and y values so we can say y=y which can be expressed as:

-7x/8+1/4=-3x/4+1/2  make all terms have a common denominator of 8

-7x/8+2/8=-6x/8+4/8  now multiply all terms by 8

-7x+2=-6x+4  add 6x to both sides

-x+2=4  subtract 2 from both sides

-x=2  divide both sides by -1

x=-2, now we solve for y using either original equation...

y=-3(-2)/4+1/2

y=6/4+1/2

y=6/4+2/4

y=8/4

y=2  so the lines intersect at the point:

(-2, 2)
iris [78.8K]3 years ago
5 0

The lines would intersect at (-2,2)

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Hello,

\dfrac{1}{(2x+3)^2} + \dfrac{2x}{(2x+3)^3} \\

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Answer:

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Step-by-step explanation:

\frac{1}{3\imath}-(-6+\frac{2}{3\imath})

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taking like terms together

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taking LCM

\frac{1-2}{3\imath}+6

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taking LCM

\frac{-1+18\imath}{3\imath}

splitting the term

\frac{-1+18\imath}{3\imath}

splitting the term

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3 years ago
Select the expression below that is equal to 5(11 - m).
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Answer:

C

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The steps Quentin took to evaluate the expression 3m - 3+3 when m = 8
kicyunya [14]

Answer:

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3 years ago
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