An equilateral triangle with side length 9 cm is shown in the diagram, work out the area of the triangle.

1. A set of weights includes a 5 lb barbell and 8 pairs of weight plates. Each pair, p,

lidiya [134]

Answer:

5 <= y <= 85

Step-by-step explanation:

Since the lowest weight possible is 5lbs (just the barbell and no weights) the lowest point of the range is 5lbs (the y intercept when x = 0)

The highest weight possible is 85lbs since, there is only 8 pairs of weight plates (8 is the input value) and the pairs each weigh 10lbs (the slope of the graph) + 5lbs from the barbell (y-intercept).

Using the function given, if you input 8 as the x value, you get

85 = 10(8) + 5

So the highest value of the range is 85lbs, therefore the range is 5 <= y <= 85.

6 0

3 years ago

If a 40,000g cannon ball is 35m above the Earth’s surface, how much potential energy does the cannon ball have?

ELEN [110]

Answer:

Step-by-step explanation:

Remark

You could do this by converting the distance but the much more common way is to use kg and m.

Formula

PE = m * g * h

Givens

m = 40000 grams

m = 40000 grams * 1kg/1000 grams = 40 kg

g = 9.81

h = 35 m

Solution

PE = 40 * 9.81 * 35

PE = 13734 Joules

4 0

3 years ago

The cost to enter the fair is $9. Ride cost $5 each write the equation to represent this problem

Llana [10]

Answer:

9+5x=t

Step-by-step explanation:

8 0

3 years ago

The price of a bicycle was decreased by 40% to £96. What was the price before the decrease?The price of a computer was decreased

Mkey [24]

The first one would be $160 and the second one would be $525

6 0

3 years ago

BRAINLIEST ✨

inna [77]

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)= 8/3, 4, 6

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)= 8/3, 4, 6Common ratio: 4/(8/3) = 3/2 same as 6/4 = 3/2. Correct.

Step-by-step explanation:

Am I right? just commet if I'm wrong

then TANKYOU>^_^<!

7 0

2 years ago