Answer:
The square root of 4096 is 64. The cube root of 4096 is 16. The fourth root of 4096 is 8 and the fifth root is 5.2780316430916.
Step-by-step explanation:
Answer:
6x - 11y = -13 is the answer.
Step-by-step explanation:
Let's plug in the points to see what sticks.
Start with (-4, -1)
1) 11x - 6y = 11(-4) - 6(-1) = -44 + 6 = -38
13
2) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13
3) 6x - 7y = 6(-4) - 7(-1) = -24 + 7 = -17
17
4) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13
13
The only one that fits is #2. Let's try the other point to be sure.
2) 6x - 11y = 6(1.5) - 11(2) = 9 - 22 = -13
Answer:
The answer is 29.25
Step-by-step explanation:
Using distributive property, the equation would be 3(9.75).
9.75*1+9.75*1+9.75*1=29.25
Answer:
x=25
Step-by-step explanation:
The angles 126 and (5x+1) are equal. The equation that is used is 5x+1=126.
To solve the equation, subtract 1 from both sides
5x+1-1=5x 126-1=125.
Simplify the equation. 5x=125
Divide both sides by 5. 5x/5=x 125/5=25
You would get x=25 eventually.
Step-by-step explanation:
Let vertical height of ladder from ground be y and
horizontal distance of the base of the ladder from the wall be x respectively.
Length of the ladder = l (constant) = 10 ft
<u>Using Pythagoras theorem</u>:

Differentiate both sides w.r.t time


<u>We know that</u> (After 1 sec, y = 6 ft and x = 8 ft ; dy/dt = 2 ft/sec)


<u>( Ignore - ive sign)</u>
Therefore, bottom of the ladder is sliding away from the wall at a speed of 1.5 ft/sec one second after the ladder starts sliding.