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vekshin1
2 years ago
8

Hurry I'm almost out of time !!!!

Mathematics
2 answers:
stich3 [128]2 years ago
8 0

Answer:

v= 7*6/2 *8 (The last one)

Step-by-step explanation:

To find the volume you have to multiply the base and the height which is 7 and 6 and divide it by 2.  Then you multiply the 8.  

djverab [1.8K]2 years ago
5 0
It is the last one because it is
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Someone help me please! will give brainliest.
Monica [59]
Answer: Graph B and Graph D
4 0
3 years ago
Find an equation of the tangent to the curve at the given point by both eliminating the parameter and without eliminating the pa
konstantin123 [22]

Answer:

y=2x-8

Step-by-step explanation:

The given parametric equation is;

x=6+ln(t),y=t^2+3

<h3><u>BY ELIMINATING THE PARAMETER</u></h3>

To eliminate the parameter we make t the subject in one equation and put it inside the other.

We make t the subject in x=6+ln(t) because it is easier.

\Rightarrow x-6=ln(t)

\Rightarrow {e}^{x-6}=e^{ln(t)}

\Rightarrow {e}^{x-6}=t

Or

t={e}^{x-6}

We now substitute this into y=t^2+3.

This gives us;

y=(e^{x-6})^2+3.

\Rightarrow y=e^{2(x-6)}+3.

We have now eliminated the parameter.

The equation of the tangent at (6,4) is given by;

y-y_1=m(x-x_1)

where the gradient function is given by;

\frac{dy}{dx}=2e^{2(x-6)}

We substitute x=6 into the gradient function to obtain the gradient.

\Rightarrow m=2e^{2(6-6)}

\Rightarrow m=2e^0

\Rightarrow m=2

The equation of the tangent becomes

y-4=2(x-6)

We simplify to obtain

y=2x-12+4

y=2x-8

<h3><u>WITHOUT ELIMINATING THE PARAMETER</u></h3>

The given parametric equation is;

x=6+ln(t),y=t^2+3

For x=6+ln(t)

\frac{dx}{dt}=\frac{1}{t}

For y=t^2+3

\frac{dy}{dt}=2t

The slope is given by;

\frac{dy}{dx}=\frac{\frac{dy}{dt} }{\frac{dx}{dt} }

\frac{dy}{dx}=\frac{2t }{\frac{1}{t} }

\frac{dy}{dx}=2t^2

At the point, (6,4), we plug in any of the values into the parametric equation and find the corresponding value for t.

Notice that

When x=6, 6=6+\ln(t)

6-6=\ln(t)

0=\ln(t)

e^0=e^\ln(t)

1=t

when y=4, 4=t^2+3

4-3=t^2

1=t^2

t=\pm1

But the slope is the same when we plug in any of these values for t.

\frac{dy}{dx}=2(\pm1)^2=2

The equation of the tangent becomes

y-4=2(x-6)

We simplify to obtain

y=2x-12+4

y=2x-8

7 0
3 years ago
The area of the base (B) of a triangular pyramid is 28 cm. The perimeter (p) is 20 cm, and the slant height (S) is 5 cm. Determi
kenny6666 [7]

Answer:

The pyramid's surface area is 78 square centimeters

Step-by-step explanation:

The formula of the surface area of a pyramid is S.A = A + \frac{1}{2} p s, where

  • A is the area of its base
  • p is the perimeter of its base
  • s is the slant height of it

∵ The area of the base of a triangular pyramid is 28 cm²

∴ A = 28 cm²

∵ The perimeter of the base is 20 cm

∴ p = 20 cm

∵ The he slant height is 5 cm

∴ s = 5 cm

- Substitute these values in the formula of the surface area

   above to find it

∵ S.A = 28 + \frac{1}{2} (20)(5)

∴ S.A = 28 + 50

∴ S.A = 78 cm²

The pyramid's surface area is 78 square centimeters

5 0
3 years ago
HELP ME ASAP I WILL GIVE BRAINIEST TO THE FIRST THAT IS CORRECT
Rudiy27

Answer:

13.7 miles

Step-by-step explanation:

If you make 6 1/3 into 6.3 and subtract that from 20, you will get 13.7 miles.

4 0
3 years ago
Angle abc and dcb make a linear pair. of abc=2x+9 and dbc=10x+15,find x
Anuta_ua [19.1K]

Answer:

x = 13

Step-by-step explanation:

A linear pair of angles sum to 180° , then

2x + 9 + 10x + 15 = 180 , that is

12x + 24 = 180 ( subtract 24 from both sides )

12x = 156 ( divide both sides by 12 )

x = 13

8 0
3 years ago
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