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3 years ago

Identify the area of segment AOB to the nearest hundredth.

Mathematics

1 answer:

scoundrel [369]3 years ago

4 0

Answer:

Area of Segment = 3.26 in² (Approx)

Step-by-step explanation:

Given:

Radius (r) = 6 in

Angle (θ) = 60°

Find:

Area of segment

Computation:

Area of Segment = (θ/360)πr² − (1/2)r²sin(θ)

Area of Segment = (60/360)(22/7)(6)² − (1/2)(6)²sin(60)

Area of Segment = (1/6)(22/7)(36) - (0.5)(36)sin(60)

Area of Segment = 18.8571429 - 15.5884573

Area of Segment = 3.2686856

Area of Segment = 3.26 in² (Approx)

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What feature do plants have that provide structure and form?

Nostrana [21]

It should be a.), all plant cells have a cell wall made of cellulose, which acts as exoskeleton and makes them so stable. However on a bigger level this plant cells can also form cellulose fibers, so that c.) is not completely false :)

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3 years ago

Is (-5, 6) a solution to y = 2x + 4 ?<br> I need an answer quickly, please

Fittoniya [83]

Answer:

(-5, 6) is not a solution.

Step-by-step explanation:

6=2(-5)+4

6=-10+4

-10+4=-6, not 6.

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3 years ago

Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge

Ede4ka [16]

Answer:

Part a) The quadratic function is $4x^{2} +20x-39=0$

Part b) The value of x is $1.5\ in$

Part c) The photo and frame together are $7\ in$ wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

$(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0$

Part b) What is the value of x?

Solve the quadratic equation $4x^{2} +20x-39=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem

we have

$4x^{2} +20x-39=0$

$a=4\\b=20\\c=-39$

substitute in the formula

$x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}$

$x=\frac{-20(+/-)\sqrt{1,024}} {8}$

$x=\frac{-20(+/-)32} {8}$

$x=\frac{-20(+)32} {8}=1.5\ in$ -----> the solution

$x=\frac{-20(-)32} {8}=-6.5\ in$

Part c) How wide are the photo and frame together?

$(4+2x)=4+2(1.5)=7\ in$

5 0

3 years ago

In triangle MPN, angle P is a right angle. If cos N= 3/5 which of the following statements is true

Bezzdna [24]

Answer: Sin N = $\frac{4}{5}$

Step-by-step explanation:

Since we have given that

In triangle MPN, ∠P=90°

$\cos N=\frac{3}{5}$

As we know the formula for "Trigonometric Ratios":

$\cos N=\frac{Base}{Hypotenuse}=\frac{3}{5}$

By Pythagorus theorem , we get

$H^2=B^2+P^2\\\\5^2=3^2+P^2\\\\25=9+P^2\\\\25-9=P^2\\\\16=P^2\\\\P=\sqrt{16}\\\\P=4\ units$

So, we get,

$\sin N=\frac{Perpendicular}{Hypotenuse}=\frac{4}{5}$

Hence, Sin N = $\frac{4}{5}$

3 0

3 years ago

Felicia bought 3 feet of ribbon for a project. she needs to cut the ribbon into 6 equal pieces. how long will each ribbon be?

anastassius [24]

3feer is 36 inches

36/6= 6 inches

6 0

3 years ago