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sergejj [24]
3 years ago
15

Order the following numbers from smallest to largest?

Mathematics
2 answers:
Alex787 [66]3 years ago
8 0
-15, -5, 0, 10, 25



Hope this helps :)
irina1246 [14]3 years ago
5 0

Answer:

-15,-5,0,10,25

Step-by-step explanation:

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Two functions are graphed on the coordinate plane.
rosijanka [135]

Answer:

Option B

Step-by-step explanation:

We can see that, from the picture provided, the graphs intersect at points( 0, 4 ) and ( - 4, 4 ), respective to functions f( x ) and g( x ). These intersection points makes each function equivalent to one another, and hence -

Function f( x ) where x = - 4 / Function g( x ) where x = - 4,

f( - 4 ) = 4,\\g( - 4 ) = 4\\----------\\f ( - 4 ) = g ( - 4 )

Respectively function f( x ) where x = 0 / Function g( x ) where x = 0,

f( 0 ) = 4,\\g( 0 ) = 4\\----------\\f ( 0 ) = g ( 0 )

<u><em>Your solution should be option b, "  f(-4) = g(-4) and f(0) = g(0) "</em></u>

7 0
2 years ago
100 POINTS! PLEASE HELP!
Semmy [17]

Apply angle bisector theorem

\\ \sf\longmapsto \dfrac{9}{15}=\dfrac{3}{5}=\dfrac{2x-1}{3x}

\\ \sf\longmapsto 9x=5(2x-1)

\\ \sf\longmapsto 9x=10x-5

\\ \sf\longmapsto 10x-9x=5

\\ \sf\longmapsto x=5

#2

\\ \sf\longmapsto \dfrac{4}{3}=\dfrac{x}{2.25}

\\ \sf\longmapsto 4(2.25)=3x

\\ \sf\longmapsto 3x=9

\\ \sf\longmapsto x=3

Hope it helps

4 0
2 years ago
Read 2 more answers
WILL GIVE BRAINLIEST IF DO QUICKLY!!!!!: Let f(x) = 2/x and g(x) = x − 3. Write an expression for f(g(x))
givi [52]

Answer:

I dont know sorry

Step-by-step explanation:

sorrrrrrry

4 0
3 years ago
A projectile is fired with muzzle speed 250 m/s and an angle of elevation 45° from a position 30 m above ground level. Where doe
qaws [65]

The projectile's horizontal and vertical positions at time t are given by

x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ\,t

y=30\,\mathrm m+\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ\,t-\dfrac g2t^2

where g=9.8\dfrac{\rm m}{\mathrm s^2}. Solve y=0 for the time t it takes for the projectile to reach the ground:

30+\dfrac{250}{\sqrt2}t-4.9t^2=0\implies t\approx36.2458\,\mathrm s

In this time, the projectile will have traveled horizontally a distance of

x=\dfrac{250\frac{\rm m}{\rm s}}{\sqrt2}(36.2458\,\mathrm s)\approx6400\,\mathrm m

The projectile's horizontal and vertical velocities are given by

v_x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ

v_y=\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ-gt

At the time the projectile hits the ground, its velocity vector has horizontal component approx. 176.77 m/s and vertical component approx. -178.43 m/s, which corresponds to a speed of about \sqrt{176.77^2+(-178.43)^2}\dfrac{\rm m}{\rm s}\approx250\dfrac{\rm m}{\rm s}.

7 0
3 years ago
Plz answer ASAP with work ty!
horsena [70]

Answer: 8\sqrt{6}

Step-by-step explanation:

\frac{2^4\sqrt{3}}{\sqrt{2}}

2^{\frac{7}{2}}\sqrt{3}

2^{\frac{7}{2}}=2^{3+\frac{1}{2}}

2^3\cdot \:2^{\frac{1}{2}}=

2^3\sqrt{2}

= 2^3\sqrt{2}\sqrt{3}=

2^3\sqrt{2\cdot \:3}

=2^3\sqrt{6}

2^3=8

Answer- 8\sqrt{6}

7 0
3 years ago
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