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CaHeK987 [17]
3 years ago
9

381.10-214.43 equals

Mathematics
1 answer:
dmitriy555 [2]3 years ago
3 0

Answer:

166.67

Step-by-step explanation:

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lutik1710 [3]
The answer would be D

8 0
3 years ago
Solve the following inequality. 5x-3 &gt; 7<br> a. x &gt; 2<br> b. x &lt; 50<br> c. x &gt; 50
Serjik [45]

Answer:

x > 2

Step-by-step explanation:

5 0
4 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B-25" id="TexFormula1" title="\sqrt{-25" alt="\sqrt{-25" align="absmiddle" class="lat
Vilka [71]

Answer:

±5i

Step-by-step explanation:

sqrt(-25)

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sqrt(-1) sqrt(25)

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±5i

3 0
3 years ago
How many consecutive zeros are there at the end of the expansion of 1,000 factorial?
Masja [62]
249 Zeros in the expansion of 1,000
3 0
4 years ago
Read 2 more answers
A rocket is launched from the top of a 99-foot cliff with an initial velocity of 122 ft/s.
Harman [31]
Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
Lets replace the values into the the vertical motion formula to get:
0=-16 t^{2} +122t+99
Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:
-99=-16 t^{2} +122t+99
-16 t^{2} +122+198=0

Now we can apply the quadratic formula t= \frac{-b+or- \sqrt{ b^{2} -4ac} }{2a} where a=-16, b=122, and c=198
t= \frac{-122+or- \sqrt{ 122^{2}-(4)(-16)(198) } }{(2)(-16)}
t= \frac{-122+ \sqrt{27556} }{-32} or t= \frac{-122- \sqrt{27556} }{-32}
t= \frac{-122+166}{-32} or t= \frac{-122-166}{-32}
t= \frac{-11}{8} or t=9

Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.
5 0
3 years ago
Read 2 more answers
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