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murzikaleks [220]
3 years ago
13

How to know the derivative of a function by looking at the graphs?

Mathematics
1 answer:
ozzi3 years ago
6 0
The derivative is the gradient.

At any local Max's or min's the derivative graph will cut the x axis.

For example a graph x^2
The derivative will have a positive gradient as the gradient is increasing at the lower values then at x=0 the gradient is 0 so the derivative graph will pass the point (0,0). Remember that the derivative graph will be linear.

To get more detail find the points the graph crosses the x axis and put into for a(x-q)(x-p)=0 you will have to solve for 'a' by finding a point on the graph and substituting it in. Then you can find the derivative of that function and graph it
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The area of a rectangle is 30 square root 3750 square inches, and the length is 3 square root 250 inches what is the width of th
Ann [662]

Answer:

width=10\sqrt{15}\ in

Step-by-step explanation:

-A rectangle's area is given by:

A=lw\\\\l=length\\w=width

Given A=30\sqrt{3750} and l=3\sqrt{250}, we substitute in the formula to solve for the width as follows:

A=lw\\\\30\sqrt{3750}=3\sqrt{250}\times w\\\\w=\frac{30\sqrt{3750}}{3\sqrt{250}}\\\\w=10\frac{\sqrt{3750}}{\sqrt{250}}\\\\=10\times \sqrt{\frac{3750}{250}}\\\\=10\sqrt{15}\ in

Hence , the rectangle's width is 10\sqrt{15}\ in

6 0
3 years ago
Can someone pls help??
Vlad1618 [11]

Answer:

a. The y coordinates for A are either 10 or -14

b.  The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

15^2 =sqrt (81+(-2-y1)^2)^2

225 =  81+(-2-y1)^2

Subtract 81 from each side

225-81 = 81-81 +(-2-y1)^2

144 = (-2-y1)^2

Take the square root of each side

±sqrt 144 = sqrt(-2-y1)^2

±12 = (-2-y1)

Add 2 to each side

2±12 = 2-2-y1

2±12 = -y1

14 = -y1  or -10 = -y1

Multiply by -1

-14 = y1  or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

15 = sqrt ((-12)^2+(-2-y1)^2)

15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

225 =  144+(-2-y1)^2

Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

81 = (-2-y1)^2

Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1  or -7 = -y1

Multiply by -1

-11 = y1  or 7 = y1

The y coordinates for A are either -11 or 7

3 0
3 years ago
The best answer gets brainliest
faltersainse [42]

Answer:

ok?

Step-by-step explanation:

Sure friend what do you need help with? I will help you

7 0
2 years ago
Read 2 more answers
Plz awnser :) but explain i actually wanna know how to do this. long division, 1300÷15=?
chubhunter [2.5K]
(Divide) 1,300÷15=86.6666666667
6 0
3 years ago
A rabbit hopped 11 meters in 6 minutes. At that rate, how far did the rabbit hop in 8 minutes?
ad-work [718]
It hopped 14 meters in 8 minutes.
6 0
3 years ago
Read 2 more answers
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