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3 years ago

How to know the derivative of a function by looking at the graphs?

1 answer:

ozzi3 years ago

6 0

The derivative is the gradient.

At any local Max's or min's the derivative graph will cut the x axis.

For example a graph x^2
The derivative will have a positive gradient as the gradient is increasing at the lower values then at x=0 the gradient is 0 so the derivative graph will pass the point (0,0). Remember that the derivative graph will be linear.

To get more detail find the points the graph crosses the x axis and put into for a(x-q)(x-p)=0 you will have to solve for 'a' by finding a point on the graph and substituting it in. Then you can find the derivative of that function and graph it

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Pls help me with these problems

Over [174]

I will help u ina sec follow me

5 0

3 years ago

The manufacturer of an airport baggage scanning machine claims it can handle an average of530 bags per hour.(a-1) At α = .05 in

-Dominant- [34]

Answer:

b. H0: μ < 530. Reject H0 if tcalc > -1.753

Step-by-step explanation:

1) Data given and notation

$\bar X=507$ represent the sample mean

$s=47$ represent the sample standard deviation

$n=16$ sample size

$\mu_o =530$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less than 530 (left tailed tes), the system of hypothesis would be:

Null hypothesis: $\mu \geq 530$

Alternative hypothesis: $\mu < 530$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{507-530}{\frac{47}{\sqrt{16}}}=-1.957$

Critical value

Since we are conducting a left tailed test we need to first find the degrees of freedom for the statistic given by:

$df=n-1=16-1=15$

Now we need to look on the t distribution with 15 degrees of freedom that accumulates 0.05 of the area on the left area. And on this case the critical value would be $t_{\alpha}=-1/753$ .

And we can use the following excel code to find it: "=T.INV(0.05,15)"

So then the correct rejection zone for H0 would be: Reject H0 if $t_{calc}$

P-value

Since is a one side left tailed test the p value would be:

$p_v =P(t_{(15)}$

Conclusion

If we compare the p value and the significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean is significantly lower than 530 at 5% of significance.

6 0

3 years ago

The sum of three consecutive integers is 915. what are the integers

ra1l [238]

(x-1)+x+(x+1)=915
3x=915
x=305

304, 305, 306

4 0

3 years ago

Make a factor tree for 16

jonny [76]

16
∧
4 X 4
∧ ∧
2 X 2 2 X 2

The answer is 2 x 2 x 2 x 2 or 2⁴ This would have worked as well had you broken

down 16 into 8 x 2. You would get the same answer as the 8 would break down into 4 x 2 and the 4 would break down into 2 x 2.

6 0

3 years ago

Which of these types of income is taxed?

icang [17]

Answer:

<h2>interest on saving accounts</h2><h2 />

Step-by-step explanation:

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3 years ago