The correct answer is, 'Resetting' the style allows the designer to start from a known baseline, confident that no unwanted styles will creep in from any browser's internal style sheet.
The study on the prevalence of coronary artery disease in patients with isolated aortic valve stenosis is given below.
<h3>What was the study about?</h3>
The prevalence of a High amount coronary artery disease (that is the lowering in luminal diameter by about 50%) is one that is seen in a lot of people such as about 88 consecutive patients and it is one where they have aortic stenosis that needs aortic valve replacement.
The study shows that the risk factors associated with coronary disease were said to be equally distributed in all of the patients with and without a good amount of luminal obstruction.
Therefore, one can say that the study on the prevalence of coronary artery disease in patients with isolated aortic valve stenosis is well done.
Learn more about coronary artery disease from
brainly.com/question/1347334
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Existen 2 clases comunes:
sistema de lazo abierto: la salida no efecto sobre el sistema
sistema de lazo cerrado: la toma de desiciones del sistema de la entrada si no también de la salida
Answer:
- equation = input("Enter an equation: ")
-
- if("+" in equation):
- operands = equation.split("+")
- result = int(operands [0]) + int(operands[1])
- print(operands[0] + "+" + operands[1] + "=" + str(result))
- elif("-" in equation):
- operands = equation.split("-")
- result= int(operands [0]) - int(operands[1])
- print(operands[0] + "-" + operands[1] + "=" + str(result))
- elif("*" in equation):
- operands = equation.split("*")
- result = int(operands [0]) * int(operands[1])
- print(operands[0] + "*" + operands[1] + "=" + str(result))
- elif("/" in equation):
- operands = equation.split("/")
- result = int(operands [0]) / int(operands[1])
- print(operands[0] + "/" + operands[1] + "=" + str(result))
- elif("%" in equation):
- operands = equation.split("%")
- result = int(operands [0]) % int(operands[1])
- print(operands[0] + "%" + operands[1] + "=" + str(result))
Explanation:
The solution code is written in Python 3.
Firstly prompt user to enter an equation using input function (Line 1).
Create if-else if statements to check if operator "+", "-", "*", "/" and "%" exist in the input equation. If "+" is found (Line 3), use split method to get the individual operands from the equation by using "+" as separator (Line 5). Output the equation as required by the question using string concatenation method (Line 6). The similar process is repeated for the rest of else if blocks (Line 7 - 22).
