Answer:
Determine a single event with a single outcome. ...
Identify the total number of outcomes that can occur. ...
Divide the number of events by the number of possible outcomes. ...
Determine each event you will calculate. ...
Calculate the probability of each event.
Step-by-step explanation:
CAN I PLS HAVE BRAINLIEST
Answer:
The answer is
<h2>20 + 56i</h2>
Step-by-step explanation:
(2 -10i) (-5 + 3i)
Using FOIL multiply each term in the first bracket by the terms in the second <u>bracket</u>
That's
2(-5) + 2(3i) - 10i(-5) - 10i(3i)
<u>Multiply the numbers and simplify</u>
We have
- 10 + 6i + 50i - 30i²
From the rules of imaginary numbers
<h3>i² = - 1</h3>
So we have
- 10 + 56i - 30(- 1)
- 10 + 56i + 30
Simplify
30 - 10 + 56i
We have the final answer as
<h3>20 + 56i</h3>
Hope this helps you
Answer:
4c² + 11cd + 5d
Step-by-step explanation:
To add monomials, you have to look at the variables that are accompanied by their coefficients. In the given problem, (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd), you can combine both cd ut nt cd and c² and cd and d and d and c² because they have different variables.
(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)
(-4c² + 8c²) + (7cd + 4cd) + (8d - 3d)
4c² + 11cd + 5d
different between A and B
=30-(-30)
=60
position of C from A or B
=(60÷3)×2
=40
possible value of c
=-30+40
=10
possible value of c
=30-40
=-10
Answer:
The positive numbers are 51 and 53
Step-by-step explanation:
Let first odd integer be x and another odd integer is (x+2).
According to the given condition,
The product of two positive consecutive odd integers is 2703 i.e.
x(x+2) = 2703
It is a quadratic equation. It can be solved as follows :
x = 51 and x = -53
Neglecting negative sign,
The first number = 51
Another number =(51+2) = 53
Hence, the positive numbers are 51 and 53.
