Answer:
angle B'CA'= angle BCA..... (common angle)
angle B'A'C = angle BAC.....(corresponding angels)
therefore,
ΔCB'A' ~ ΔCBA. ......(by A-A test of similarity)
therefore,
B'A'/ BA. = CA'/ CA....(congruent sides of congruent triangles)
now, B'A' = 5, CA'= 6 , CA = 6 + 3 = 9
5 / BA. = 6 / 9
therefore, 5 / BA. = 2 / 3
Answer : AB = 7.5 units
Answer:So first, I found the length of the sides and the diagonal of the square, which are 18−−√ and 6 respectively. By graphing, I know the solution is (0,−1). Then, I assume that since the length between (3,2) and (−3,2) is the diagonal, then the distance between (0,5) and the remaining vertex must be the diagonal too. And since the length of the side is 6, then the distance between the vertex and either (3,2) or (−3,2) must be 6. So:
(x−3)2+(y−2)2−−−−−−−−−−−−−−−√=18−−√
(x−0)2+(y−5)2−−−−−−−−−−−−−−−√=6
Which gives (after a bit of cleaning up):
x2+y2−10y=11
x2−6x+y2−4y=5
Then, replacing the second expression into the first one:
x2−6x+y2−4y=5⇒x2=5+6x−y2+4y
5+6x−y2+4y+y2−10y=11
5+6x+4y−10y=11
6x−6y+6
x−y=1
x=1+y
Up to this point, I know I'm not entirely wrong because the expression is true for the actual coordinates of the vertex, because 0=1+(−1) is true. But I wouldn't know how to proceed if I hadn't known the answer beforehand. I need to find both x and y, is there a linear equation I'm missing to find the exact coordinates of the last vertex? Is my process okay or is there a simpler way to do it?
Step-by-step explanation:
Answer:
6 you are welcome I hope this helps
ANSWER: $44.10
EXPLANATION: The actual cost for an ice hockey match is $19.60. Now, if the price of the ticket increases by 12.5%, the cost of each ticket will increase by $2.45.
$19.6 x 12.5% = $2.45
So, the final price of a single ticket will be $22.05
$19.6 + $2.45 = $22.05
Hence, the cost of two tickets after the increase will be $44.10
$22.05 x 2 = $44.10
Answer:
6 because that is where the paarabola crosses the y line
Step-by-step explanation:
